All;
I have created a table that looks like this:
CREATE TABLE myschema.cust_part (
cust_int_id bigint,
cust_ext_id bigint,
cust_tax_id varchar(20),
cust_dob date,
cust_dob_str varchar(20),
cust_last_name varchar(100),
cust_first_name varchar(100),
cust_middle_name varchar(100),
cust_addr1 text,
cust_city text,
cust_state text,
cust_zip varchar(5)
) PARTITION BY LIST (cust_last_name);
and a partition that looks like this:
CREATE TABLE part_schema.cust_info_5
PARTITION OF myschema.cust_part
FOR VALUES IN ('NELL');
if I insert ONLY the partition key column via a select from another
table it fails:
INSERT INTO part_schema.cust_info_5
( cust_last_name)
SELECT l_name from public.global_addr WHERE l_name = 'NELL';
ERROR: new row for relation "cust_info_5" violates partition constraint
DETAIL: Failing row containd (null, null, null, null, null, 'NELL',
null, null, null, null, null,null).
However if I insert the values directly it works:
INSERT INTO part_schema.cust_info_5 VALUES (null, null, null, null,
null, 'NELL', null, null, null, null, null,null)
;
INSERT 0 1
I'm stumped, this happens with other last name values as well such as
'N', and 'SMITH' thoughts?
I get the same behavior if I insert based on a select of all the
partition table columns
Thanks in advance
