Thread: ERROR Inserting into partition

ERROR Inserting into partition

From
Sbob
Date:
All;


I have created a table that looks like this:

CREATE TABLE myschema.cust_part (
            cust_int_id     bigint,
           cust_ext_id    bigint,
           cust_tax_id   varchar(20),
           cust_dob        date,
           cust_dob_str   varchar(20),
          cust_last_name  varchar(100),
         cust_first_name   varchar(100),
          cust_middle_name  varchar(100),
         cust_addr1                text,
        cust_city                     text,
        cust_state                  text,
        cust_zip                     varchar(5)
) PARTITION BY LIST (cust_last_name);

and a partition that looks like this:

CREATE TABLE part_schema.cust_info_5
PARTITION OF myschema.cust_part
FOR VALUES IN ('NELL');



if I insert ONLY the partition  key column  via a select from another 
table it fails:

INSERT INTO part_schema.cust_info_5
( cust_last_name)
SELECT l_name from public.global_addr WHERE l_name = 'NELL';
ERROR:  new row for relation "cust_info_5" violates partition constraint
DETAIL:  Failing row containd (null, null, null, null, null, 'NELL', 
null, null, null, null, null,null).

However if I insert the values directly it works:

INSERT INTO part_schema.cust_info_5 VALUES (null, null, null, null, 
null, 'NELL', null, null, null, null, null,null)
;
INSERT 0 1



I'm stumped, this happens with other last name values as well such as 
'N', and 'SMITH' thoughts?

I get the same behavior if I insert based on a select of all the 
partition table columns

Thanks in advance





Re: ERROR Inserting into partition

From
"David G. Johnston"
Date:

INSERT INTO part_schema.cust_info_5
( cust_last_name)
SELECT l_name from public.global_addr WHERE l_name = 'NELL';
ERROR:  new row for relation "cust_info_5" violates partition constraint
DETAIL:  Failing row containd (null, null, null, null, null, 'NELL',
null, null, null, null, null,null).


Your to: address for this email is so confusing...and this really isn't either a performance issue (meaning speed, not failure to perform at all) or admin issue (general advice for running the server).  It seems like a bug report, though one missing the most critical piece of information, the version.

David J.

Re: ERROR Inserting into partition

From
"David G. Johnston"
Date:
On Tue, Oct 22, 2024 at 7:36 AM Sbob <sbob@quadratum-braccas.com> wrote:

INSERT INTO part_schema.cust_info_5
( cust_last_name)
SELECT l_name from public.global_addr WHERE l_name = 'NELL';
ERROR:  new row for relation "cust_info_5" violates partition constraint
DETAIL:  Failing row containd (null, null, null, null, null, 'NELL',
null, null, null, null, null,null).


Also, I am unable to reproduce this in development:

CREATE TABLE cust_part (
            cust_int_id     bigint,
           cust_ext_id    bigint,
           cust_tax_id   varchar(20),
           cust_dob        date,
           cust_dob_str   varchar(20),
          cust_last_name  varchar(100),
         cust_first_name   varchar(100),
          cust_middle_name  varchar(100),
         cust_addr1                text,
        cust_city                     text,
        cust_state                  text,
        cust_zip                     varchar(5)
) PARTITION BY LIST (cust_last_name);

CREATE TABLE cust_info_5
PARTITION OF cust_part
FOR VALUES IN ('NELL');

create table global_addr (l_name text);

insert into global_addr values ('NELL');

INSERT INTO cust_info_5
( cust_last_name)
SELECT l_name from global_addr WHERE l_name = 'NELL';

David J.

Re: ERROR Inserting into partition

From
Sbob
Date:

Thanks, it turns out it was subtle user error


On 10/22/24 8:53 AM, David G. Johnston wrote:
On Tue, Oct 22, 2024 at 7:36 AM Sbob <sbob@quadratum-braccas.com> wrote:

INSERT INTO part_schema.cust_info_5
( cust_last_name)
SELECT l_name from public.global_addr WHERE l_name = 'NELL';
ERROR:  new row for relation "cust_info_5" violates partition constraint
DETAIL:  Failing row containd (null, null, null, null, null, 'NELL',
null, null, null, null, null,null).


Also, I am unable to reproduce this in development:

CREATE TABLE cust_part (
            cust_int_id     bigint,
           cust_ext_id    bigint,
           cust_tax_id   varchar(20),
           cust_dob        date,
           cust_dob_str   varchar(20),
          cust_last_name  varchar(100),
         cust_first_name   varchar(100),
          cust_middle_name  varchar(100),
         cust_addr1                text,
        cust_city                     text,
        cust_state                  text,
        cust_zip                     varchar(5)
) PARTITION BY LIST (cust_last_name);

CREATE TABLE cust_info_5
PARTITION OF cust_part
FOR VALUES IN ('NELL');

create table global_addr (l_name text);

insert into global_addr values ('NELL');

INSERT INTO cust_info_5
( cust_last_name)
SELECT l_name from global_addr WHERE l_name = 'NELL';

David J.