Hello,
I'd like to get the path configured for archive_command in a shell script
I've used a file with following content as an example (postgresql.conf),
# archive_command = cp %p /backup/%r
# archive_command = cp %p /backup/%r
# archive_command = cp %p /backup/%r
#archive_command = cp %p /backup/%r
archive_command = 'cp %p /backup/wal/%f'
This is what I been trying.
$ awk '!/[ \t]*#/ { sub(/%f$/, "", $NF); print $NF }' postgresql.conf
and I get
/backup/wal/%f'
Any idea how to get rid of "%f'" so that I get only?
/backup/wal/
My regexp skills are sad :-)
Steve
