Re: BUG #15724: Can't create foreign table as partition - Mailing list pgsql-bugs

From Amit Langote
Subject Re: BUG #15724: Can't create foreign table as partition
Date
Msg-id 038a0fec-6684-c654-bade-bcf80cb8daad@lab.ntt.co.jp
Whole thread Raw
In response to Re: BUG #15724: Can't create foreign table as partition  (Etsuro Fujita <fujita.etsuro@lab.ntt.co.jp>)
Responses Re: BUG #15724: Can't create foreign table as partition
List pgsql-bugs
On 2019/04/01 14:35, Etsuro Fujita wrote:
> (2019/03/29 23:10), Alvaro Herrera wrote:
>> On 2019-Mar-29, Tom Lane wrote:
>>
>>> Alvaro Herrera<alvherre@2ndquadrant.com>  writes:
>>>> On 2019-Mar-29, PG Bug reporting form wrote:
>>>>> SQL Error [42809]: ERROR: cannot create index on foreign table
>>>>> "msg_json"
> 
>>> Really, what *ought* to happen in such a case is that the FDW gets
>>> told about the command and has the opportunity to try to do something
>>> corresponding to making an index.
> 
> Interesting!

+1

Maybe, CHECK constraints on foreign tables are similar -- it merely
asserts the condition that all of the rows in the remote table *must*
satisfy so that the local server can do something useful with it, such as
trying to exclude the table with constraint exclusion.

I guess the intended benefit with allowing indexes would be similar -- a
locally-defined index on a foreign table will help an FDW estimate the
cost of a query accessing the table more efficiently than, for example,
having to rely on some other relatively expensive alternative, such as
use_remote_estimate in postgres_fdw's case.

Thanks,
Amit




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