Re: BUG #15724: Can't create foreign table as partition - Mailing list pgsql-bugs

From Etsuro Fujita
Subject Re: BUG #15724: Can't create foreign table as partition
Date
Msg-id 5CA1A320.4050707@lab.ntt.co.jp
Whole thread Raw
In response to Re: BUG #15724: Can't create foreign table as partition  (Alvaro Herrera <alvherre@2ndquadrant.com>)
Responses Re: BUG #15724: Can't create foreign table as partition  (Amit Langote <Langote_Amit_f8@lab.ntt.co.jp>)
List pgsql-bugs
(2019/03/29 23:10), Alvaro Herrera wrote:
> On 2019-Mar-29, Tom Lane wrote:
>
>> Alvaro Herrera<alvherre@2ndquadrant.com>  writes:
>>> On 2019-Mar-29, PG Bug reporting form wrote:
>>>> SQL Error [42809]: ERROR: cannot create index on foreign table "msg_json"

>> Really, what *ought* to happen in such a case is that the FDW gets
>> told about the command and has the opportunity to try to do something
>> corresponding to making an index.

Interesting!

>> corresponding to making an index.  But that smells like a new feature
>> rather than a bug fix.

> ENOTIME to get it done for pg12 I suppose (I don't know a thing about
> postgres_fdw or the FDW API layer).

Yeah, I think so.

>> I'm not sure that just forcing the case to be a no-op is wise.
>> What if the index is supposed to be UNIQUE?
>
> Hmm, good point, that should be disallowed too.

Agreed.

Best regards,
Etsuro Fujita




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