Thread: left outer join only select newest record
Hi folks, I know I've seen posts like this before but Google isn't helping today. I have two tables, vehicle stock and tax requests. Each vehicle can be taxed more than once, but I only want to pull in the most recent tax request - the one with the highest ud_id. I have the following, which obviously returning multiple records which then appears that the same vehicle is in stock multiple times. How can I make it so we only show each vehicle once, showing the most recent tax request details. select * from stock_details s left outer join used_diary u on s.s_registration = u.ud_registration; -- Gary Stainburn Group I.T. Manager Ringways Garages http://www.ringways.co.uk
Gary, You describe two tables vehicle stock and tax requests. The former has a one-to-many relationship wit the second one, right? But your query involves stock details and used_diary. What is the relationship of these two new tables to the previous ones? Could you please kindly supply an example of what you have and of the desired output? For me it would be easier... Best, Oliver ----- Original Message ----- From: "Gary Stainburn" <gary.stainburn@ringways.co.uk> To: <pgsql-sql@postgresql.org> Sent: Wednesday, May 23, 2012 10:27 AM Subject: [SQL] left outer join only select newest record > Hi folks, > > I know I've seen posts like this before but Google isn't helping today. > > I have two tables, vehicle stock and tax requests. Each vehicle can be > taxed > more than once, but I only want to pull in the most recent tax request - > the > one with the highest ud_id. > > I have the following, which obviously returning multiple records which > then > appears that the same vehicle is in stock multiple times. How can I make > it > so we only show each vehicle once, showing the most recent tax request > details. > > > select * from stock_details s > left outer join used_diary u on s.s_registration = u.ud_registration; > > > -- > Gary Stainburn > Group I.T. Manager > Ringways Garages > http://www.ringways.co.uk > > -- > Sent via pgsql-sql mailing list (pgsql-sql@postgresql.org) > To make changes to your subscription: > http://www.postgresql.org/mailpref/pgsql-sql
2012/5/23 Gary Stainburn <gary.stainburn@ringways.co.uk>: > Hi folks, > > I know I've seen posts like this before but Google isn't helping today. > > I have two tables, vehicle stock and tax requests. Each vehicle can be taxed > more than once, but I only want to pull in the most recent tax request - the > one with the highest ud_id. > > I have the following, which obviously returning multiple records which then > appears that the same vehicle is in stock multiple times. How can I make it > so we only show each vehicle once, showing the most recent tax request > details. > > > select * from stock_details s > left outer join used_diary u on s.s_registration = u.ud_registration; select distinct on (s.s_registration) *... order by u.ud_id desc or select * from stock_details s left join (select * from used_diary where (ud_id, ud_registration) = (select max(ud_id), ud_registration from used_diary group by ud_registration)) x on s.s_registration = x.ud_registration; Regards Pavel Stehule > > > -- > Gary Stainburn > Group I.T. Manager > Ringways Garages > http://www.ringways.co.uk > > -- > Sent via pgsql-sql mailing list (pgsql-sql@postgresql.org) > To make changes to your subscription: > http://www.postgresql.org/mailpref/pgsql-sql
Appologies for not making it clearer. stock_details is simply a view of table stock, pulling in some lookup values. used_diary is the name of the table containing the tax requests. It's called the used_diary because it was the diary for taxing used vehicles. Here is a select to show the problem. There is one stock record and two tax records. What I'm looking for is how I can return only the second tax record, the one with the highest ud_id select s_stock_no, s_regno, s_vin, s_created, ud_id, ud_handover_date from stock s left outer join used_diary u on s.s_regno = u.ud_pex_registration where s_stock_no = 'UL15470'; s_stock_no | s_regno | s_vin | s_created | ud_id | ud_handover_date ------------+---------+-------------------+----------------------------+-------+------------------UL15470 | YG12*** |KNADN312LC6****** | 2012-05-21 09:15:31.569471 | 41892 | 2012-04-06UL15470 | YG12*** | KNADN312LC6****** | 2012-05-21 09:15:31.569471 | 42363 | 2012-05-16 (2 rows) On Wednesday 23 May 2012 10:37:31 Oliveiros d'Azevedo Cristina wrote: > Gary, > > You describe two tables vehicle stock and tax requests. The former has a > one-to-many relationship wit the second one, right? > > But your query involves stock details and used_diary. > > What is the relationship of these two new tables to the previous ones? > > Could you please kindly supply an example of what you have and of the > desired output? For me it would be easier... > > Best, > Oliver > > ----- Original Message ----- > From: "Gary Stainburn" <gary.stainburn@ringways.co.uk> > To: <pgsql-sql@postgresql.org> > Sent: Wednesday, May 23, 2012 10:27 AM > Subject: [SQL] left outer join only select newest record > > > Hi folks, > > > > I know I've seen posts like this before but Google isn't helping today. > > > > I have two tables, vehicle stock and tax requests. Each vehicle can be > > taxed > > more than once, but I only want to pull in the most recent tax request - > > the > > one with the highest ud_id. > > > > I have the following, which obviously returning multiple records which > > then > > appears that the same vehicle is in stock multiple times. How can I make > > it > > so we only show each vehicle once, showing the most recent tax request > > details. > > > > > > select * from stock_details s > > left outer join used_diary u on s.s_registration = u.ud_registration; > > > > > > -- > > Gary Stainburn > > Group I.T. Manager > > Ringways Garages > > http://www.ringways.co.uk > > > > -- > > Sent via pgsql-sql mailing list (pgsql-sql@postgresql.org) > > To make changes to your subscription: > > http://www.postgresql.org/mailpref/pgsql-sql -- Gary Stainburn Group I.T. Manager Ringways Garages http://www.ringways.co.uk
Gary Stainburn, 23.05.2012 11:47: > Here is a select to show the problem. There is one stock record and two tax > records. What I'm looking for is how I can return only the second tax record, > the one with the highest ud_id > > select s_stock_no, s_regno, s_vin, s_created, ud_id, ud_handover_date from > stock s left outer join used_diary u on s.s_regno = u.ud_pex_registration > where s_stock_no = 'UL15470'; > > s_stock_no | s_regno | s_vin | s_created | > ud_id | ud_handover_date > ------------+---------+-------------------+----------------------------+-------+------------------ > UL15470 | YG12*** | KNADN312LC6****** | 2012-05-21 09:15:31.569471 | > 41892 | 2012-04-06 > UL15470 | YG12*** | KNADN312LC6****** | 2012-05-21 09:15:31.569471 | > 42363 | 2012-05-16 > (2 rows) > Something like: select * from ( select s_stock_no, s_regno s_vin, s_created, ud_id, ud_handover_date, row_number() over (partition by s_stock_no order by ud_id desc) as rn from stock s leftouter join used_diary u on s.s_regno = u.ud_pex_registration where s_stock_no = 'UL15470' ) t where rn = 1 The "partition by s_stock_no order" isn't really necessary as your where clause already limits that to a single stock_no. But in case you change that statement to return more than one stock_no in the future it will be necessary.
Hello again, Gary, I don't know if this query works OK, i havent tried it. But, If I understood correctly this can be one way to do what you want. Could you please tell me if it worked and if it didn't why, so we can tweak it. Best, Oliver SELECT subq.s_stock_no,subq.s_regno,subq.s_vin,subq.s_created,subq.m, sec.s_creacted FROM (select s_stock_no, s_regno, s_vin, s_created, MAX(ud_id) as m from stock s left outer join used_diary u on s.s_regno = u.ud_pex_registrationwhere s_stock_no = 'UL15470'; GROUP s_stock_no,s_regno,s_vin,s_created ) subq JOIN used_diary sec ON subq.m = sec.ud_id ----- Original Message ----- From: "Gary Stainburn" <gary.stainburn@ringways.co.uk> To: <pgsql-sql@postgresql.org> Sent: Wednesday, May 23, 2012 10:47 AM Subject: Re: [SQL] left outer join only select newest record > Appologies for not making it clearer. stock_details is simply a view of > table > stock, pulling in some lookup values. used_diary is the name of the table > containing the tax requests. It's called the used_diary because it was the > diary for taxing used vehicles. > > Here is a select to show the problem. There is one stock record and two > tax > records. What I'm looking for is how I can return only the second tax > record, > the one with the highest ud_id > > select s_stock_no, s_regno, s_vin, s_created, ud_id, ud_handover_date from > stock s left outer join used_diary u on s.s_regno = u.ud_pex_registration > where s_stock_no = 'UL15470'; > > s_stock_no | s_regno | s_vin | s_created | > ud_id | ud_handover_date > ------------+---------+-------------------+----------------------------+-------+------------------ > UL15470 | YG12*** | KNADN312LC6****** | 2012-05-21 09:15:31.569471 | > 41892 | 2012-04-06 > UL15470 | YG12*** | KNADN312LC6****** | 2012-05-21 09:15:31.569471 | > 42363 | 2012-05-16 > (2 rows) > > > On Wednesday 23 May 2012 10:37:31 Oliveiros d'Azevedo Cristina wrote: >> Gary, >> >> You describe two tables vehicle stock and tax requests. The former has a >> one-to-many relationship wit the second one, right? >> >> But your query involves stock details and used_diary. >> >> What is the relationship of these two new tables to the previous ones? >> >> Could you please kindly supply an example of what you have and of the >> desired output? For me it would be easier... >> >> Best, >> Oliver >> >> ----- Original Message ----- >> From: "Gary Stainburn" <gary.stainburn@ringways.co.uk> >> To: <pgsql-sql@postgresql.org> >> Sent: Wednesday, May 23, 2012 10:27 AM >> Subject: [SQL] left outer join only select newest record >> >> > Hi folks, >> > >> > I know I've seen posts like this before but Google isn't helping today. >> > >> > I have two tables, vehicle stock and tax requests. Each vehicle can be >> > taxed >> > more than once, but I only want to pull in the most recent tax >> > request - >> > the >> > one with the highest ud_id. >> > >> > I have the following, which obviously returning multiple records which >> > then >> > appears that the same vehicle is in stock multiple times. How can I >> > make >> > it >> > so we only show each vehicle once, showing the most recent tax request >> > details. >> > >> > >> > select * from stock_details s >> > left outer join used_diary u on s.s_registration = u.ud_registration; >> > >> > >> > -- >> > Gary Stainburn >> > Group I.T. Manager >> > Ringways Garages >> > http://www.ringways.co.uk >> > >> > -- >> > Sent via pgsql-sql mailing list (pgsql-sql@postgresql.org) >> > To make changes to your subscription: >> > http://www.postgresql.org/mailpref/pgsql-sql > > > > -- > Gary Stainburn > Group I.T. Manager > Ringways Garages > http://www.ringways.co.uk > > -- > Sent via pgsql-sql mailing list (pgsql-sql@postgresql.org) > To make changes to your subscription: > http://www.postgresql.org/mailpref/pgsql-sql
Sorry, Gary, I made a mistake on the last column. It should be SELECT subq.s_stock_no,subq.s_regno,subq.s_vin,subq.s_created,subq.m, sec.ud_handover_date FROM (select s_stock_no, s_regno, s_vin, s_created, MAX(ud_id) as m from stock s left outer join used_diary u on s.s_regno = u.ud_pex_registrationwhere s_stock_no = 'UL15470'; GROUP s_stock_no,s_regno,s_vin,s_created ) subq JOIN used_diary sec ON subq.m = sec.ud_id Best, Oliver ----- Original Message ----- From: "Oliveiros d'Azevedo Cristina" <oliveiros.cristina@marktest.pt> To: "Gary Stainburn" <gary.stainburn@ringways.co.uk>; <pgsql-sql@postgresql.org> Sent: Wednesday, May 23, 2012 11:29 AM Subject: Re: [SQL] left outer join only select newest record > Hello again, Gary, > > I don't know if this query works OK, i havent tried it. > > But, If I understood correctly this can be one way to do what you want. > Could you please tell me if it worked and if it didn't why, so we can > tweak it. > > Best, > Oliver > > SELECT subq.s_stock_no,subq.s_regno,subq.s_vin,subq.s_created,subq.m, > sec.s_creacted > FROM > (select s_stock_no, s_regno, s_vin, s_created, MAX(ud_id) as m > from stock s > left outer join used_diary u > on s.s_regno = u.ud_pex_registration > where s_stock_no = 'UL15470'; > GROUP s_stock_no,s_regno,s_vin,s_created > ) subq > JOIN > used_diary sec > ON subq.m = sec.ud_id > > ----- Original Message ----- > From: "Gary Stainburn" <gary.stainburn@ringways.co.uk> > To: <pgsql-sql@postgresql.org> > Sent: Wednesday, May 23, 2012 10:47 AM > Subject: Re: [SQL] left outer join only select newest record > > >> Appologies for not making it clearer. stock_details is simply a view of >> table >> stock, pulling in some lookup values. used_diary is the name of the >> table >> containing the tax requests. It's called the used_diary because it was >> the >> diary for taxing used vehicles. >> >> Here is a select to show the problem. There is one stock record and two >> tax >> records. What I'm looking for is how I can return only the second tax >> record, >> the one with the highest ud_id >> >> select s_stock_no, s_regno, s_vin, s_created, ud_id, ud_handover_date >> from >> stock s left outer join used_diary u on s.s_regno = u.ud_pex_registration >> where s_stock_no = 'UL15470'; >> >> s_stock_no | s_regno | s_vin | s_created | >> ud_id | ud_handover_date >> ------------+---------+-------------------+----------------------------+-------+------------------ >> UL15470 | YG12*** | KNADN312LC6****** | 2012-05-21 09:15:31.569471 | >> 41892 | 2012-04-06 >> UL15470 | YG12*** | KNADN312LC6****** | 2012-05-21 09:15:31.569471 | >> 42363 | 2012-05-16 >> (2 rows) >> >> >> On Wednesday 23 May 2012 10:37:31 Oliveiros d'Azevedo Cristina wrote: >>> Gary, >>> >>> You describe two tables vehicle stock and tax requests. The former has a >>> one-to-many relationship wit the second one, right? >>> >>> But your query involves stock details and used_diary. >>> >>> What is the relationship of these two new tables to the previous ones? >>> >>> Could you please kindly supply an example of what you have and of the >>> desired output? For me it would be easier... >>> >>> Best, >>> Oliver >>> >>> ----- Original Message ----- >>> From: "Gary Stainburn" <gary.stainburn@ringways.co.uk> >>> To: <pgsql-sql@postgresql.org> >>> Sent: Wednesday, May 23, 2012 10:27 AM >>> Subject: [SQL] left outer join only select newest record >>> >>> > Hi folks, >>> > >>> > I know I've seen posts like this before but Google isn't helping >>> > today. >>> > >>> > I have two tables, vehicle stock and tax requests. Each vehicle can be >>> > taxed >>> > more than once, but I only want to pull in the most recent tax >>> > request - >>> > the >>> > one with the highest ud_id. >>> > >>> > I have the following, which obviously returning multiple records which >>> > then >>> > appears that the same vehicle is in stock multiple times. How can I >>> > make >>> > it >>> > so we only show each vehicle once, showing the most recent tax request >>> > details. >>> > >>> > >>> > select * from stock_details s >>> > left outer join used_diary u on s.s_registration = u.ud_registration; >>> > >>> > >>> > -- >>> > Gary Stainburn >>> > Group I.T. Manager >>> > Ringways Garages >>> > http://www.ringways.co.uk >>> > >>> > -- >>> > Sent via pgsql-sql mailing list (pgsql-sql@postgresql.org) >>> > To make changes to your subscription: >>> > http://www.postgresql.org/mailpref/pgsql-sql >> >> >> >> -- >> Gary Stainburn >> Group I.T. Manager >> Ringways Garages >> http://www.ringways.co.uk >> >> -- >> Sent via pgsql-sql mailing list (pgsql-sql@postgresql.org) >> To make changes to your subscription: >> http://www.postgresql.org/mailpref/pgsql-sql > > > -- > Sent via pgsql-sql mailing list (pgsql-sql@postgresql.org) > To make changes to your subscription: > http://www.postgresql.org/mailpref/pgsql-sql
On Wednesday 23 May 2012 10:46:02 Pavel Stehule wrote: > select distinct on (s.s_registration) * > ... order by u.ud_id desc I tried doing this but it complained about the order by. goole=# select distinct on (s.s_stock_no) s_stock_no, s_regno, s_vin, s_created, ud_id, ud_handover_date from stock s left outer join used_diary u on s.s_regno = u.ud_pex_registration where s_stock_no = 'UL15470' order by s_stock_no, ud_id desc; ERROR: SELECT DISTINCT ON expressions must match initial ORDER BY expressions goole=# select distinct on (s.s_stock_no) s_stock_no, s_regno, s_vin, s_created, ud_id, ud_handover_date from stock s left outer join used_diary u on s.s_regno = u.ud_pex_registration where s_stock_no = 'UL15470' order by ud_id desc; ERROR: SELECT DISTINCT ON expressions must match initial ORDER BY expressions goole=# > > or > > select * > from stock_details s > left join (select * from used_diary where (ud_id, > ud_registration) = (select max(ud_id), ud_registration from used_diary > group by ud_registration)) x > on s.s_registration = x.ud_registration; > This was more like what I was thinking, but I still get an error, which I don't understand. I have extracted the inner sub-select and it does only return one record per registration. (The extra criteria is just to ignore old or cancelled tax requests and doesn't affect the query) goole=# select distinct on (s.s_stock_no) s_stock_no, s_regno, s_vin, s_created, ud_id, ud_handover_date from stock s left outer join (select ud_id, ud_pex_registration, ud_handover_date from used_diary where (ud_id, ud_pex_registration) = (select max(ud_id), ud_pex_registration from used_diary where (ud_tab is null or ud_tab <> 999) and ud_created > CURRENT_DATE-'4 months'::interval group by ud_pex_registration)) udIn on s.s_regno = udIn.ud_pex_registration; ERROR: more than one row returned by a subquery used as an expression
> > This was more like what I was thinking, but I still get an error, which I > don't understand. I have extracted the inner sub-select and it does only > return one record per registration. (The extra criteria is just to ignore old > or cancelled tax requests and doesn't affect the query) > > goole=# select distinct on (s.s_stock_no) s_stock_no, s_regno, s_vin, > s_created, ud_id, ud_handover_date from stock s left outer join (select > ud_id, ud_pex_registration, ud_handover_date from used_diary where (ud_id, > ud_pex_registration) = (select max(ud_id), ud_pex_registration from > used_diary where (ud_tab is null or ud_tab <> 999) and ud_created > > CURRENT_DATE-'4 months'::interval group by ud_pex_registration)) udIn on > s.s_regno = udIn.ud_pex_registration; > ERROR: more than one row returned by a subquery used as an expression sure, I am sorry please, WHERE (ud_id, ud_pex_registration) = (SELECT ... replace by WHERE (..) IN (SELECT .. Regards Pavel > > -- > Sent via pgsql-sql mailing list (pgsql-sql@postgresql.org) > To make changes to your subscription: > http://www.postgresql.org/mailpref/pgsql-sql
On Thursday 24 May 2012 09:17:00 Pavel Stehule wrote: > please, WHERE (ud_id, ud_pex_registration) = (SELECT ... > > replace by > > WHERE (..) IN (SELECT .. > > Regards > > Pavel Worked perfectly, thank you -- Gary Stainburn Group I.T. Manager Ringways Garages http://www.ringways.co.uk
Hi, Gary, Unless I'm mistaken this didn't give what you need. Could you please tell me (if you have time) the error returned or wrong result, just for my own understanding of where I've gone sideways on this...? Best, Oliver ----- Original Message ----- From: "Oliveiros d'Azevedo Cristina" <oliveiros.cristina@marktest.pt> To: "Oliveiros d'Azevedo Cristina" <oliveiros.cristina@marktest.pt>; "Gary Stainburn" <gary.stainburn@ringways.co.uk>; <pgsql-sql@postgresql.org> Sent: Wednesday, May 23, 2012 11:41 AM Subject: Re: [SQL] left outer join only select newest record > Sorry, Gary, > > I made a mistake on the last column. > > It should be > > SELECT subq.s_stock_no,subq.s_regno,subq.s_vin,subq.s_created,subq.m, > sec.ud_handover_date > FROM > (select s_stock_no, s_regno, s_vin, s_created, MAX(ud_id) as m > from stock s > left outer join used_diary u > on s.s_regno = u.ud_pex_registration > where s_stock_no = 'UL15470'; > GROUP s_stock_no,s_regno,s_vin,s_created > ) subq > JOIN > used_diary sec > ON subq.m = sec.ud_id > > Best, > Oliver > ----- Original Message ----- > From: "Oliveiros d'Azevedo Cristina" <oliveiros.cristina@marktest.pt> > To: "Gary Stainburn" <gary.stainburn@ringways.co.uk>; > <pgsql-sql@postgresql.org> > Sent: Wednesday, May 23, 2012 11:29 AM > Subject: Re: [SQL] left outer join only select newest record > > >> Hello again, Gary, >> >> I don't know if this query works OK, i havent tried it. >> >> But, If I understood correctly this can be one way to do what you want. >> Could you please tell me if it worked and if it didn't why, so we can >> tweak it. >> >> Best, >> Oliver >> >> SELECT subq.s_stock_no,subq.s_regno,subq.s_vin,subq.s_created,subq.m, >> sec.s_creacted >> FROM >> (select s_stock_no, s_regno, s_vin, s_created, MAX(ud_id) as m >> from stock s >> left outer join used_diary u >> on s.s_regno = u.ud_pex_registration >> where s_stock_no = 'UL15470'; >> GROUP s_stock_no,s_regno,s_vin,s_created >> ) subq >> JOIN >> used_diary sec >> ON subq.m = sec.ud_id >> >> ----- Original Message ----- >> From: "Gary Stainburn" <gary.stainburn@ringways.co.uk> >> To: <pgsql-sql@postgresql.org> >> Sent: Wednesday, May 23, 2012 10:47 AM >> Subject: Re: [SQL] left outer join only select newest record >> >> >>> Appologies for not making it clearer. stock_details is simply a view of >>> table >>> stock, pulling in some lookup values. used_diary is the name of the >>> table >>> containing the tax requests. It's called the used_diary because it was >>> the >>> diary for taxing used vehicles. >>> >>> Here is a select to show the problem. There is one stock record and two >>> tax >>> records. What I'm looking for is how I can return only the second tax >>> record, >>> the one with the highest ud_id >>> >>> select s_stock_no, s_regno, s_vin, s_created, ud_id, ud_handover_date >>> from >>> stock s left outer join used_diary u on s.s_regno = >>> u.ud_pex_registration >>> where s_stock_no = 'UL15470'; >>> >>> s_stock_no | s_regno | s_vin | s_created | >>> ud_id | ud_handover_date >>> ------------+---------+-------------------+----------------------------+-------+------------------ >>> UL15470 | YG12*** | KNADN312LC6****** | 2012-05-21 09:15:31.569471 | >>> 41892 | 2012-04-06 >>> UL15470 | YG12*** | KNADN312LC6****** | 2012-05-21 09:15:31.569471 | >>> 42363 | 2012-05-16 >>> (2 rows) >>> >>> >>> On Wednesday 23 May 2012 10:37:31 Oliveiros d'Azevedo Cristina wrote: >>>> Gary, >>>> >>>> You describe two tables vehicle stock and tax requests. The former has >>>> a >>>> one-to-many relationship wit the second one, right? >>>> >>>> But your query involves stock details and used_diary. >>>> >>>> What is the relationship of these two new tables to the previous ones? >>>> >>>> Could you please kindly supply an example of what you have and of the >>>> desired output? For me it would be easier... >>>> >>>> Best, >>>> Oliver >>>> >>>> ----- Original Message ----- >>>> From: "Gary Stainburn" <gary.stainburn@ringways.co.uk> >>>> To: <pgsql-sql@postgresql.org> >>>> Sent: Wednesday, May 23, 2012 10:27 AM >>>> Subject: [SQL] left outer join only select newest record >>>> >>>> > Hi folks, >>>> > >>>> > I know I've seen posts like this before but Google isn't helping >>>> > today. >>>> > >>>> > I have two tables, vehicle stock and tax requests. Each vehicle can >>>> > be >>>> > taxed >>>> > more than once, but I only want to pull in the most recent tax >>>> > request - >>>> > the >>>> > one with the highest ud_id. >>>> > >>>> > I have the following, which obviously returning multiple records >>>> > which >>>> > then >>>> > appears that the same vehicle is in stock multiple times. How can I >>>> > make >>>> > it >>>> > so we only show each vehicle once, showing the most recent tax >>>> > request >>>> > details. >>>> > >>>> > >>>> > select * from stock_details s >>>> > left outer join used_diary u on s.s_registration = u.ud_registration; >>>> > >>>> > >>>> > -- >>>> > Gary Stainburn >>>> > Group I.T. Manager >>>> > Ringways Garages >>>> > http://www.ringways.co.uk >>>> > >>>> > -- >>>> > Sent via pgsql-sql mailing list (pgsql-sql@postgresql.org) >>>> > To make changes to your subscription: >>>> > http://www.postgresql.org/mailpref/pgsql-sql >>> >>> >>> >>> -- >>> Gary Stainburn >>> Group I.T. Manager >>> Ringways Garages >>> http://www.ringways.co.uk >>> >>> -- >>> Sent via pgsql-sql mailing list (pgsql-sql@postgresql.org) >>> To make changes to your subscription: >>> http://www.postgresql.org/mailpref/pgsql-sql >> >> >> -- >> Sent via pgsql-sql mailing list (pgsql-sql@postgresql.org) >> To make changes to your subscription: >> http://www.postgresql.org/mailpref/pgsql-sql >