Re: left outer join only select newest record - Mailing list pgsql-sql
From | Oliveiros d'Azevedo Cristina |
---|---|
Subject | Re: left outer join only select newest record |
Date | |
Msg-id | 58025C771D674FCC8A6F2C08E8D10CF6@marktestcr.marktest.pt Whole thread Raw |
In response to | left outer join only select newest record (Gary Stainburn <gary.stainburn@ringways.co.uk>) |
List | pgsql-sql |
Hi, Gary, Unless I'm mistaken this didn't give what you need. Could you please tell me (if you have time) the error returned or wrong result, just for my own understanding of where I've gone sideways on this...? Best, Oliver ----- Original Message ----- From: "Oliveiros d'Azevedo Cristina" <oliveiros.cristina@marktest.pt> To: "Oliveiros d'Azevedo Cristina" <oliveiros.cristina@marktest.pt>; "Gary Stainburn" <gary.stainburn@ringways.co.uk>; <pgsql-sql@postgresql.org> Sent: Wednesday, May 23, 2012 11:41 AM Subject: Re: [SQL] left outer join only select newest record > Sorry, Gary, > > I made a mistake on the last column. > > It should be > > SELECT subq.s_stock_no,subq.s_regno,subq.s_vin,subq.s_created,subq.m, > sec.ud_handover_date > FROM > (select s_stock_no, s_regno, s_vin, s_created, MAX(ud_id) as m > from stock s > left outer join used_diary u > on s.s_regno = u.ud_pex_registration > where s_stock_no = 'UL15470'; > GROUP s_stock_no,s_regno,s_vin,s_created > ) subq > JOIN > used_diary sec > ON subq.m = sec.ud_id > > Best, > Oliver > ----- Original Message ----- > From: "Oliveiros d'Azevedo Cristina" <oliveiros.cristina@marktest.pt> > To: "Gary Stainburn" <gary.stainburn@ringways.co.uk>; > <pgsql-sql@postgresql.org> > Sent: Wednesday, May 23, 2012 11:29 AM > Subject: Re: [SQL] left outer join only select newest record > > >> Hello again, Gary, >> >> I don't know if this query works OK, i havent tried it. >> >> But, If I understood correctly this can be one way to do what you want. >> Could you please tell me if it worked and if it didn't why, so we can >> tweak it. >> >> Best, >> Oliver >> >> SELECT subq.s_stock_no,subq.s_regno,subq.s_vin,subq.s_created,subq.m, >> sec.s_creacted >> FROM >> (select s_stock_no, s_regno, s_vin, s_created, MAX(ud_id) as m >> from stock s >> left outer join used_diary u >> on s.s_regno = u.ud_pex_registration >> where s_stock_no = 'UL15470'; >> GROUP s_stock_no,s_regno,s_vin,s_created >> ) subq >> JOIN >> used_diary sec >> ON subq.m = sec.ud_id >> >> ----- Original Message ----- >> From: "Gary Stainburn" <gary.stainburn@ringways.co.uk> >> To: <pgsql-sql@postgresql.org> >> Sent: Wednesday, May 23, 2012 10:47 AM >> Subject: Re: [SQL] left outer join only select newest record >> >> >>> Appologies for not making it clearer. stock_details is simply a view of >>> table >>> stock, pulling in some lookup values. used_diary is the name of the >>> table >>> containing the tax requests. It's called the used_diary because it was >>> the >>> diary for taxing used vehicles. >>> >>> Here is a select to show the problem. There is one stock record and two >>> tax >>> records. What I'm looking for is how I can return only the second tax >>> record, >>> the one with the highest ud_id >>> >>> select s_stock_no, s_regno, s_vin, s_created, ud_id, ud_handover_date >>> from >>> stock s left outer join used_diary u on s.s_regno = >>> u.ud_pex_registration >>> where s_stock_no = 'UL15470'; >>> >>> s_stock_no | s_regno | s_vin | s_created | >>> ud_id | ud_handover_date >>> ------------+---------+-------------------+----------------------------+-------+------------------ >>> UL15470 | YG12*** | KNADN312LC6****** | 2012-05-21 09:15:31.569471 | >>> 41892 | 2012-04-06 >>> UL15470 | YG12*** | KNADN312LC6****** | 2012-05-21 09:15:31.569471 | >>> 42363 | 2012-05-16 >>> (2 rows) >>> >>> >>> On Wednesday 23 May 2012 10:37:31 Oliveiros d'Azevedo Cristina wrote: >>>> Gary, >>>> >>>> You describe two tables vehicle stock and tax requests. The former has >>>> a >>>> one-to-many relationship wit the second one, right? >>>> >>>> But your query involves stock details and used_diary. >>>> >>>> What is the relationship of these two new tables to the previous ones? >>>> >>>> Could you please kindly supply an example of what you have and of the >>>> desired output? For me it would be easier... >>>> >>>> Best, >>>> Oliver >>>> >>>> ----- Original Message ----- >>>> From: "Gary Stainburn" <gary.stainburn@ringways.co.uk> >>>> To: <pgsql-sql@postgresql.org> >>>> Sent: Wednesday, May 23, 2012 10:27 AM >>>> Subject: [SQL] left outer join only select newest record >>>> >>>> > Hi folks, >>>> > >>>> > I know I've seen posts like this before but Google isn't helping >>>> > today. >>>> > >>>> > I have two tables, vehicle stock and tax requests. Each vehicle can >>>> > be >>>> > taxed >>>> > more than once, but I only want to pull in the most recent tax >>>> > request - >>>> > the >>>> > one with the highest ud_id. >>>> > >>>> > I have the following, which obviously returning multiple records >>>> > which >>>> > then >>>> > appears that the same vehicle is in stock multiple times. How can I >>>> > make >>>> > it >>>> > so we only show each vehicle once, showing the most recent tax >>>> > request >>>> > details. >>>> > >>>> > >>>> > select * from stock_details s >>>> > left outer join used_diary u on s.s_registration = u.ud_registration; >>>> > >>>> > >>>> > -- >>>> > Gary Stainburn >>>> > Group I.T. Manager >>>> > Ringways Garages >>>> > http://www.ringways.co.uk >>>> > >>>> > -- >>>> > Sent via pgsql-sql mailing list (pgsql-sql@postgresql.org) >>>> > To make changes to your subscription: >>>> > http://www.postgresql.org/mailpref/pgsql-sql >>> >>> >>> >>> -- >>> Gary Stainburn >>> Group I.T. Manager >>> Ringways Garages >>> http://www.ringways.co.uk >>> >>> -- >>> Sent via pgsql-sql mailing list (pgsql-sql@postgresql.org) >>> To make changes to your subscription: >>> http://www.postgresql.org/mailpref/pgsql-sql >> >> >> -- >> Sent via pgsql-sql mailing list (pgsql-sql@postgresql.org) >> To make changes to your subscription: >> http://www.postgresql.org/mailpref/pgsql-sql >