Thread: join problem

join problem

From
"A. R. Van Hook"
Date:
I have three tables relating to purchases     invoice      - transaction data (customer id, deposit. etc)
invoiceitems- purachace items detail     cai          - customer data
 
if I query for the total charges using  select sum(rowtot + tax)   from invoiceitems  where ivid in (select ivid from
invoicewhere cusid = 2128)"
 

I get 1179.24 which is correct.

if I query for the total deposit using  select sum(deposit)  from invoice  where cusid = 2128"

I also get 1179.24, also the correct amount


If I try an inclusive query using the following:    select     sum(i.rowtot + i.tax) as tot,     sum(v.deposit) as
deposit  from cai c   join invoice           v on (v.cusid = c.cusid)   left join invoiceitems i on (v.ivid = i.ivid)
wherev.cusid = 2128   group by      c.cusid
 
I get   tot    | deposit
----------+---------1179.240 | 2819.24

Can someone correct the query?


thanks



tables definations are as follows:
invoice        (ivid                int NOT NULL PRIMARY KEY,        rid                 int null references registry,
     sid                 int not null  references staffname,        cusid               int,        invdate
date,       ifname              varchar(16),        imi                 char,        ilname              varchar(16),
    addr                text,        city                varchar(16),        state               varchar(2),        zip
               varchar(16),        iphone              varchar(16),        eventdate           date,        paytype
       int,        bust                varchar(16),        height              varchar(16),        dressize
varchar(16),       waist               varchar(16),        hips                varchar(16),        hollow
varchar(16),       deposit             numeric(6,2),        transtype           int,        notes               text,
    neck                varchar(16),        arm_length          varchar(16),        leg_length          varchar(16),
   coat                varchar(16),        shoe                varchar(16),        tux                 int    default
0

invoiceItems        (item                int NOT NULL,        ivid                int NOT NULL references invoice ON
DELETE
 
CASCADE,        qty                 int,        stid                int  references stock, /*tag*/        descript
     text,        price               numeric(6,2),        tax                 numeric(7,3),        discount
numeric(6,2),       rowtot              numeric(7,3),        pickup              int default 0,   /* SO or to be picked
up= 
 
1 */        primary key    (item, ivid)

create table cai        /* customer account  information*/      (cusid                int NOT null primary key,
cfname              varchar(16),       cmi                  char  default '',       clname               varchar(16),
   caddr                text,       ccity                varchar(16),       cstate               varchar(2),       czip
               varchar(16),       cphone               varchar(16),       db                   numeric(7,2),
tcode               int not null default 0,       acode                int not null default 0,       tdate
 timestamp not null
 
[hook@f6 ~]$


-- 
Arthur R. Van Hook    Mayor - RetiredThe City of Lake Lotawana

hook@lake-lotawana.mo.us
hook@lota.us
avanhook3@comcast.net
(816) 578-4704 - Home





Re: join problem

From
Ragnar
Date:
On fim, 2007-06-21 at 08:46 -0500, A. R. Van Hook wrote:
> if I query for the total deposit using
>    select sum(deposit)
>    from invoice
>    where cusid = 2128"
> 
> I also get 1179.24, also the correct amount
> 
> 
> If I try an inclusive query using the following:
>      select
>       sum(i.rowtot + i.tax) as tot,
>       sum(v.deposit) as deposit
>     from cai c
>     join invoice           v on (v.cusid = c.cusid)
>     left join invoiceitems i on (v.ivid = i.ivid)
>     where v.cusid = 2128
>     group by 
>       c.cusid
> I get
>     tot    | deposit
> ----------+---------
>  1179.240 | 2819.24

you are adding the invoice deposit once for each item

gnari




Re: join problem

From
"A. R. Van Hook"
Date:
What is the correct query???

thanks

Ragnar wrote:
> On fim, 2007-06-21 at 08:46 -0500, A. R. Van Hook wrote:
>   
>> if I query for the total deposit using
>>    select sum(deposit)
>>    from invoice
>>    where cusid = 2128"
>>
>> I also get 1179.24, also the correct amount
>>
>>
>> If I try an inclusive query using the following:
>>      select
>>       sum(i.rowtot + i.tax) as tot,
>>       sum(v.deposit) as deposit
>>     from cai c
>>     join invoice           v on (v.cusid = c.cusid)
>>     left join invoiceitems i on (v.ivid = i.ivid)
>>     where v.cusid = 2128
>>     group by 
>>       c.cusid
>> I get
>>     tot    | deposit
>> ----------+---------
>>  1179.240 | 2819.24
>>     
>
> you are adding the invoice deposit once for each item
>
> gnari
>
>
>
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>
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-- 
Arthur R. Van Hook    Mayor - RetiredThe City of Lake Lotawana

hook@lake-lotawana.mo.us
hook@lota.us
avanhook3@comcast.net
(816) 578-4704 - Home
(816) 564-0769 - Cell




Re: join problem

From
Ragnar
Date:
On lau, 2007-06-23 at 04:15 -0500, A. R. Van Hook wrote:
> Ragnar wrote:
> > On fim, 2007-06-21 at 08:46 -0500, A. R. Van Hook wrote:
> >> If I try an inclusive query using the following:
> >>      select
> >>       sum(i.rowtot + i.tax) as tot,
> >>       sum(v.deposit) as deposit
> >>     from cai c
> >>     join invoice           v on (v.cusid = c.cusid)
> >>     left join invoiceitems i on (v.ivid = i.ivid)
> >>     where v.cusid = 2128
> >>     group by 
> >>       c.cusid
> >> I get
> >>     tot    | deposit
> >> ----------+---------
> >>  1179.240 | 2819.24
> >
> > you are adding the invoice deposit once for each item
> >
> What is the correct query???

sum each invoice separately, and then group the sums by cusid.

for example:

select vcusid as cusid,      sum(vtot) as tot,      sum(vdeposit) as deposit
from (      select         v.cusid as vcusid,         v.ivid as vivid,         sum(i.rowtot + i.tax) as vtot,
sum(v.deposit)/count(*)as vdeposit      from invoice as v            left join invoiceitems as i  on (v.ivid = i.ivid)
   group by v.cusid,               v.ivid    ) as vsums
 
where vsums.vcusid=2128
group by vsums.vcusid


hope this helps
gnari




Re: join problem

From
"A. R. Van Hook"
Date:
Works great.
Can you enlighten me as why the deposit is divided by the number of rows?

thanks

Ragnar wrote:
> On lau, 2007-06-23 at 04:15 -0500, A. R. Van Hook wrote:
>   
>> Ragnar wrote:
>>     
>>> On fim, 2007-06-21 at 08:46 -0500, A. R. Van Hook wrote:
>>>       
>>>> If I try an inclusive query using the following:
>>>>      select
>>>>       sum(i.rowtot + i.tax) as tot,
>>>>       sum(v.deposit) as deposit
>>>>     from cai c
>>>>     join invoice           v on (v.cusid = c.cusid)
>>>>     left join invoiceitems i on (v.ivid = i.ivid)
>>>>     where v.cusid = 2128
>>>>     group by 
>>>>       c.cusid
>>>> I get
>>>>     tot    | deposit
>>>> ----------+---------
>>>>  1179.240 | 2819.24
>>>>         
>>> you are adding the invoice deposit once for each item
>>>
>>>       
>> What is the correct query???
>>     
>
> sum each invoice separately, and then group the sums by cusid.
>
> for example:
>
> select vcusid as cusid,
>        sum(vtot) as tot,
>        sum(vdeposit) as deposit
> from (
>        select
>           v.cusid as vcusid,
>           v.ivid as vivid,
>           sum(i.rowtot + i.tax) as vtot,
>           sum(v.deposit)/count(*) as vdeposit
>        from invoice as v 
>             left join invoiceitems as i  on (v.ivid = i.ivid)
>        group by v.cusid,
>                 v.ivid
>      ) as vsums
> where vsums.vcusid=2128
> group by vsums.vcusid
>
>
> hope this helps
> gnari
>
>
>
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>
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-- 
Arthur R. Van Hook    Mayor - RetiredThe City of Lake Lotawana

hook@lake-lotawana.mo.us
hook@lota.us
avanhook3@comcast.net
(816) 578-4704 - Home
(816) 564-0769 - Cell




Re: join problem

From
Ragnar
Date:
On sun, 2007-06-24 at 06:14 -0500, A. R. Van Hook wrote:

[ in the future, please avoid top-posting, as it is annoying 
to have to rearrange lines when replying ]

> Ragnar wrote:
> > On lau, 2007-06-23 at 04:15 -0500, A. R. Van Hook wrote:
> >> Ragnar wrote:
> >>> On fim, 2007-06-21 at 08:46 -0500, A. R. Van Hook wrote:
> >>>       
> >>>> [problem involving a join, with sum on base table column]

> >>> you are adding the invoice deposit once for each item
> >>>       
> >> What is the correct query???
> >
> > sum each invoice separately, and then group the sums by cusid.
> >
> > for example:
> >       ...
> >           sum(v.deposit)/count(*) as vdeposit
> >        from invoice as v 
> >             left join invoiceitems as i  on (v.ivid = i.ivid)
> >        group by v.cusid,
> >                 v.ivid
> >       ...

> Works great.
> Can you enlighten me as why the deposit is divided by the number of rows?

maybe an example would clarify a bit:

say you have only one invoice (deposit=100), 
with 2 invoiceitems (both with rowtot=50)

"select sum(deposit) from invoice" returns 100
"select sum(rowtot) from invoiceitems" returns 100

the query: select ivid,deposit,rowtot     from invoice     left join invoiceitems          on (invoice.ivid =
invoiceitems.ivid)
returns the rows:
ivid | deposit | rowtot
1    | 100     | 50
1    | 100     | 50

if you just select a SUM(deposit) on that join,
you get 200, not 100 because the value is repeated
for each invoiceitem.

hope this helps

gnari