Works great.
Can you enlighten me as why the deposit is divided by the number of rows?
thanks
Ragnar wrote:
> On lau, 2007-06-23 at 04:15 -0500, A. R. Van Hook wrote:
>
>> Ragnar wrote:
>>
>>> On fim, 2007-06-21 at 08:46 -0500, A. R. Van Hook wrote:
>>>
>>>> If I try an inclusive query using the following:
>>>> select
>>>> sum(i.rowtot + i.tax) as tot,
>>>> sum(v.deposit) as deposit
>>>> from cai c
>>>> join invoice v on (v.cusid = c.cusid)
>>>> left join invoiceitems i on (v.ivid = i.ivid)
>>>> where v.cusid = 2128
>>>> group by
>>>> c.cusid
>>>> I get
>>>> tot | deposit
>>>> ----------+---------
>>>> 1179.240 | 2819.24
>>>>
>>> you are adding the invoice deposit once for each item
>>>
>>>
>> What is the correct query???
>>
>
> sum each invoice separately, and then group the sums by cusid.
>
> for example:
>
> select vcusid as cusid,
> sum(vtot) as tot,
> sum(vdeposit) as deposit
> from (
> select
> v.cusid as vcusid,
> v.ivid as vivid,
> sum(i.rowtot + i.tax) as vtot,
> sum(v.deposit)/count(*) as vdeposit
> from invoice as v
> left join invoiceitems as i on (v.ivid = i.ivid)
> group by v.cusid,
> v.ivid
> ) as vsums
> where vsums.vcusid=2128
> group by vsums.vcusid
>
>
> hope this helps
> gnari
>
>
>
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