Thread: RE: [SQL] Function returning multiple rows?
Not currently. > -----Original Message----- > From: Patrik Kudo [mailto:kudo@partitur.se] > Sent: Friday, February 05, 1999 9:54 AM > To: pgsql-sql@postgreSQL.org > Subject: [SQL] Function returning multiple rows? > > > Hello, > > I've been trying to create a function which returns multiple > rows, but I > can't get it working. I'm I doing something wrong, or is it not > possible? This is my setup: > > create table groups (userid int4, grp int4); > > CREATE FUNCTION usersingroup(int4) RETURNS int4 AS 'SELECT userid FROM > groups WHERE grp = $1;' LANGUAGE 'sql'; > > > When doing a > > SELECT usersingroup(100); > > I only get the first row. Is there any way to get all the rows? > > Regards, > Patrik Kudo > kudo@partitur.se >
> > Not currently. Partly right. We cannot return multiple row's (at least the return values aren't useful). But an SQL language function can return multiple results. Only works for SQL language, not C or PL. > > > -----Original Message----- > > From: Patrik Kudo [mailto:kudo@partitur.se] > > Sent: Friday, February 05, 1999 9:54 AM > > To: pgsql-sql@postgreSQL.org > > Subject: [SQL] Function returning multiple rows? > > > > > > Hello, > > > > I've been trying to create a function which returns multiple > > rows, but I > > can't get it working. I'm I doing something wrong, or is it not > > possible? This is my setup: > > > > create table groups (userid int4, grp int4); > > > > CREATE FUNCTION usersingroup(int4) RETURNS int4 AS 'SELECT userid FROM > > groups WHERE grp = $1;' LANGUAGE 'sql'; CREATE FUNCTION usersingroup(int4) RETURNS SETOF int4 AS ' SELECT userid FROM groups WEHRE grp = $1; ' LANGUAGE 'sql'; > > > > > > When doing a > > > > SELECT usersingroup(100); > > > > I only get the first row. Is there any way to get all the rows? With the above you'll get multiple results. The magic word is SETOF. Jan -- #======================================================================# # It's easier to get forgiveness for being wrong than for being right. # # Let's break this rule - forgive me. # #======================================== jwieck@debis.com (Jan Wieck) #