Thread: Question about ranking & full text
Hi,
I wonder why the third query returns 0.
To me, it would return 0.1, because there is not baz in the text
Thanks !
(pg 9.4)
SELECT ts_rank_cd(apod.t, query,4) AS rank
FROM (SELECT to_tsvector('foo baz') as t) as apod, to_tsquery('foo & baz') query
WHERE query @@ apod.t;
rank |
------------|
0.100000001 |
SELECT ts_rank_cd(apod.t, query,4) AS rank
FROM (SELECT to_tsvector('foo ') as t) as apod, to_tsquery('foo & ! baz') query
WHERE query @@ apod.t;
rank |
------------|
0.100000001 |
SELECT ts_rank_cd(apod.t, query,4) AS rank
FROM (SELECT to_tsvector('foo ') as t) as apod, to_tsquery(' ! baz') query
WHERE query @@ apod.t;
rank |
------------|
0.0 |
On 15.04.2016 15:47, Nicolas Paris wrote: > Hi, > I wonder why the third query returns 0. > To me, it would return 0.1, because there is not baz in the text > > Thanks ! > (pg 9.4) > > SELECT ts_rank_cd(apod.t, query,4) AS rank > FROM (SELECT to_tsvector('foo baz') as t) as apod, to_tsquery('foo & > baz') query > WHERE query @@ apod.t; > rank | > ------------| > 0.100000001 | > > SELECT ts_rank_cd(apod.t, query,4) AS rank > FROM (SELECT to_tsvector('foo ') as t) as apod, to_tsquery('foo & ! > baz') query > WHERE query @@ apod.t; > > rank | > ------------| > 0.100000001 | > > SELECT ts_rank_cd(apod.t, query,4) AS rank > FROM (SELECT to_tsvector('foo ') as t) as apod, to_tsquery(' ! baz') query > WHERE query @@ apod.t; > > rank | > ------------| > 0.0 | > > Hello, I think this is a right behaviour of the function. Because it computes how often the query terms appear in the document, how close together the terms are in the document, and how important is the part of the document where they occur. In the third example found terms are empty. And the function can't do calculates with empty terms. It sees that the terms are empty and returns 0.0. -- Artur Zakirov Postgres Professional: http://www.postgrespro.com Russian Postgres Company