On 9/28/05, Tom Lane <tgl@sss.pgh.pa.us> wrote:
> Ian Meyer <ianmmeyer@gmail.com> writes:
> > IF TG_OP = 'DELETE' AND OLD.deleted = FALSE THEN
>
> > ERROR: record "old" is not assigned yet
> > DETAIL: The tuple structure of a not-yet-assigned record is indeterminate.
> > CONTEXT: PL/pgSQL function "thread_sync" line 2 at if
>
> > What am I failing to understand with this?
>
> We don't guarantee short-circuit evaluation of boolean expressions.
> You'll have to break that into two IFs, ie,
>
> IF TG_OP = 'DELETE' THEN
> IF ... test on OLD.something ...
>
> regards, tom lane
>
Ah ha.. that makes sense. I fixed it to be:
CREATE OR REPLACE FUNCTION thread_sync() RETURNS trigger AS $$
BEGIN IF TG_OP = 'DELETE' THEN UPDATE member SET total_threads=total_threads-1 WHERE id=OLD.member_id; RETURN OLD;
ELSEIFTG_OP = 'INSERT' THEN UPDATE member SET total_threads=total_threads+1 WHERE id=NEW.member_id; RETURN NEW;
ELSEIFTG_OP = 'UPDATE' THEN IF NEW.deleted != OLD.deleted THEN IF NEW.deleted = TRUE THEN UPDATE member SET
total_threads=total_threads-1WHERE id=NEW.member_id; RETURN NEW; ELSEIF NEW.deleted = FALSE then UPDATE
memberSET total_threads=total_threads+1 WHERE id=NEW.member_id; RETURN NEW; END IF; RETURN NULL; END
IF; RETURN NULL; END IF;
END;
$$ LANGUAGE plpgsql;
Here's my next question(s)... If i have 2 rows in the thread table and
I delete 1 of the rows with: delete from thread where id=26; it ends
up decrementing the total_threads value by 2, instead of one.
bcodev=> select id, total_threads from member;id | total_threads
----+--------------- 1 | 2
(1 row)
bcodev=> delete from thread where id=37;
DELETE 1
bcodev=> select id, total_threads from member;id | total_threads
----+--------------- 1 | 0
(1 row)
I'm confused, to say the least.
Thanks for all the help.
Ian
