why not use the date_part function again...
select date_part('dow',day), day, userid from bschft_days where
date_part('month', day) = '3';
hth
tamsin
-----Original Message-----
From: pgsql-general-owner@postgresql.org
[mailto:pgsql-general-owner@postgresql.org]On Behalf Of Jose Manuel
Lorenzo Lopez
Sent: 17 July 2001 15:25
To: PGSQL
Subject: [GENERAL] How to find out the weekday from a date???
Hello PG's,
I want to extract the weekday of a given 'date' type field in my table
when selecting. How can I do this?
For example in a table "bschft_days" filled with values with type 'date'
I want to select all the days within the month 'march' and output the
respective
weekday. I tryed this:
select extract(dow from timestamp(day)), day, userid from bschft_days where
date_part('month', day) = '3';
But it only tells me:
ERROR: parser: parse error at or near "dow"
:(
Any ideas??
Thanks a lot in advance!
Best Regards / Mit freundlichen Grüßen / Un saludo
José Manuel lorenzo López
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