On 12/23/24 08:46, Divyansh Gupta JNsThMAudy wrote: > Also as you ask how 50 pairs turns into 50 column so each column will be > a key and the value of that key will store inside their respective > column for each row
My problem with understanding this is 50 pairs = 100 values, I don't understand how that can fit in 50 columns that can only handle 1 value each. You need to provide some example data showing what you want to achieve. It does not need to be the full 50, just something to show the process.
Because the column name is the same as a dictionary key...
