On 12/23/24 08:55, David G. Johnston wrote:
> On Mon, Dec 23, 2024, 09:54 Adrian Klaver <adrian.klaver@aklaver.com
> <mailto:adrian.klaver@aklaver.com>> wrote:
>
> On 12/23/24 08:46, Divyansh Gupta JNsThMAudy wrote:
> > Also as you ask how 50 pairs turns into 50 column so each column
> will be
> > a key and the value of that key will store inside their respective
> > column for each row
>
> My problem with understanding this is 50 pairs = 100 values, I don't
> understand how that can fit in 50 columns that can only handle 1 value
> each. You need to provide some example data showing what you want to
> achieve. It does not need to be the full 50, just something to show the
> process.
>
>
>
> Because the column name is the same as a dictionary key...
Aah, got it thanks.
>
> David J.
>
>
--
Adrian Klaver
adrian.klaver@aklaver.com
