Re: POC, WIP: OR-clause support for indexes - Mailing list pgsql-hackers

From Peter Geoghegan
Subject Re: POC, WIP: OR-clause support for indexes
Date
Msg-id CAH2-Wzn4wMQ5=Y3Z-nkS-ujvibpvMuGSGD_=wVnxC2qDo=+U_w@mail.gmail.com
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In response to Re: POC, WIP: OR-clause support for indexes  (Alexander Korotkov <aekorotkov@gmail.com>)
Responses Re: POC, WIP: OR-clause support for indexes
Re: POC, WIP: OR-clause support for indexes
List pgsql-hackers
On Fri, Oct 4, 2024 at 2:00 PM Alexander Korotkov <aekorotkov@gmail.com> wrote:
> Yes, transformAExprIn() does the work to coerce all the expressions in
> the right part to the same type.  Similar logic could be implemented
> in match_orclause_to_indexcol().  What worries me is whether it's
> quite late stage for this kind of work.  transformAExprIn() works
> during parse stage, when we need to to resolve types, operators etc.
> And we do that once.

I agree that it would be a bit awkward. Especially having spent so
much time talking about doing this later on, not during parsing. That
doesn't mean that it's necessarily the wrong thing to do, though.

> If we replicate the same logic to
> match_orclause_to_indexcol(), then we may end up with index scan using
> one operator and sequential scan using another operator.

But that's already true today. For example, these two queries use
different operators at runtime, assuming both use a B-Tree index scan:

select * from tenk1 where four = any('{0,1}'::int[]) and four =
any('{1,2}'::bigint[]);

select * from tenk1 where four = any('{1,2}'::bigint[]) and four =
any('{0,1}'::int[]); -- flip the order of the arrays, change nothing
else

This isn't apparent from what EXPLAIN ANALYZE output shows, but the
fact is that only one operator (and one array) will be used at
runtime, after nbtree preprocessing completes. I'm not entirely sure
how this kind of difference might affect a sequential scan. I imagine
that it can use either or both operators unpredictably.

> Given we
> only use implicit casts for types coercion those are suppose to be
> strong equivalents.  And that's for sure true for builtin types and
> operators. But isn't it too much to assume the same for all
> extensions?

Anything is possible. But wouldn't that also mean that the extensions
were broken with the existing IN() list thing, in transformAExprIn()?
What's the difference, fundamentally?

--
Peter Geoghegan



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