On Fri, Jul 25, 2014 at 12:48 PM, Kyotaro HORIGUCHI <
horiguchi.kyotaro@lab.ntt.co.jp> wrote:
> > I think there is one more disadvantage in the way current patch is
> > done which is that you need to collect index path keys for all relations
> > irrespective of whether they will be of any use to eliminate useless
> > pathkeys from query_pathkeys. One trivial case that comes to mind is
> > when there are multiple relations involved in query and ORDER BY is
> > base on columns of only part of the tables involved in query.
>
> Like this?
>
> select x.a, x.b, y.b from x, y where x.a = y.a order by x.a, x.b;
>
> Equivalent class consists of (x.a=y.a) and (x.b), so index
> pathkeys for i_y is (y.a.=x.a). As a result, no common primary
> pathkeys found.
I think it will find common pathkey incase you have an unique index
on x.a (please see the example below), but currently I am not clear
why there is a need for a common index path key in such a case to
eliminate useless keys in ORDER BY, why can't we do it based
on individual table's path key.
Example:
create table t (a int not null, b int not null, c int, d text);
create unique index i_t_pkey on t(a, b);
insert into t (select a % 10, a / 10, a, 't' from generate_series(0, 100000) a);
analyze;
create table t1 (a int not null, b int not null, c int, d text);
create unique index i_t1_pkey_1 on t1(a);
create unique index i_t1_pkey_2 on t1(a, b);
insert into t1 (select a * 2, a / 10, a, 't' from generate_series(0, 100000) a);
explain (costs off, analyze off) select * from t,t1 where t.a=t1.a order by t1.a,t1.b,t1.c,t1.d;
QUERY PLAN
------------------------------------------
Merge Join
Merge Cond: (t.a = t1.a)
-> Index Scan using i_t_pkey on t
-> Index Scan using i_t1_pkey_1 on t1
(4 rows)
Here we can notice that there is no separate sort key in plan.
Now drop the i_t1_pkey_1 and check the query plan again.
drop index i_t1_pkey_1;
explain (costs off, analyze off) select * from t,t1 where t.a=t1.a order by t1.a,t1.b,t1.c,t1.d;
QUERY PLAN
------------------------------------------------
Sort
Sort Key: t.a, t1.b, t1.c, t1.d
-> Merge Join
Merge Cond: (t.a = t1.a)
-> Index Scan using i_t_pkey on t
-> Index Scan using i_t1_pkey_2 on t1
(6 rows)
Can't above plan eliminate Sort Key even after dropping index
(i_t1_pkey_1)?
