"Ross J. Reedstrom" <reedstrm@rice.edu> writes:
> And here's the working example: not the need to GROUP BY, and <=
> to get the current payment.
> select cust_id,invoice_id,val,paid, (select (sum(val) - sum(paid))
> from invoices_not_paid where cust_id= i.cust_id and invoice_id <=
> i.invoice_id group by cust_id) as balance from invoices_not_paid i;
Actually I think you could leave off the inner GROUP BY --- won't there
always be exactly one group, since only one value of inner cust_id is
selected?
regards, tom lane
