Re: Incremental sum ? - Mailing list pgsql-sql

From Ross J. Reedstrom
Subject Re: Incremental sum ?
Date
Msg-id 20010622112119.D13451@rice.edu
Whole thread Raw
In response to Re: Incremental sum ?  (Alex Pilosov <alex@pilosoft.com>)
Responses Re: Incremental sum ?
List pgsql-sql
And here's the working example: not the need to GROUP BY, and <=
to get the current payment.

select cust_id,invoice_id,val,paid, (select (sum(val) - sum(paid))
from invoices_not_paid where cust_id= i.cust_id and invoice_id <=
i.invoice_id group by cust_id) as balance  from invoices_not_paid i;

and it's output:
cust_id | invoice_id |    val    |   paid   |  balance  
---------+------------+-----------+----------+-----------      1 |         23 | 10.500000 | 3.400000 |  7.100000      1
|        34 |  5.700000 | 0.000000 | 12.800000      1 |         67 | 23.890000 | 4.500000 | 32.190000
 
(3 rows)

Ross

On Fri, Jun 22, 2001 at 11:29:25AM -0400, Alex Pilosov wrote:
> It should be done using subqueries.
> select ..., (
>    select sum(val)-sum(paid) from invoices i2
>    where i2.invoice_id<i.invoice_id
>      and i2.cust_id=i.cust_id
>    )
> from invoices i
> 
> 
> On 22 Jun 2001, Domingo Alvarez Duarte wrote:
> 
> > I have a problem that requires what I call a incremental sum, lets say
> > I have the folowing table (for simplicity):
> > 
> > table invoices_not_paid(cust_id int, invoice_id int, val numeric, paid
> > numeric);
> > 
> > with the folowing values:
> > 
> > cust_id   invoice_id   val    paid
> > ----------------------------------
> > 1             23      10.50   3.40
> > 1             34       5.70   0.0
> > 1             67      23.89   4.50
> > 
> > 
> > I want show a list like this:
> > 
> > cust_id   invoice_id   val    paid  incremental_not_paid_sum
> > -----------------------------------------------------------------
> > 1             23      10.50   3.40     (10.50 - 3.40)        7.10
> > 1             34       5.70   0.0    (7.10 + 5.70 - 0.0)    12.80
> > 1             67      23.89   4.50  (12.80 + 23.89 - 4.50)  31.19
> > 
> > The operations betwen () are showed only to explain how the
> > incremental_not_paid_sum is calculated, The operation requires a
> > reference to a previous column or a partial sum of columns till that
> > moment, someone has an idea how this can be done using sql ?
> > 
> > ---------------------------(end of broadcast)---------------------------
> > TIP 4: Don't 'kill -9' the postmaster
> > 
> > 
> 
> 
> ---------------------------(end of broadcast)---------------------------
> TIP 6: Have you searched our list archives?
> 
> http://www.postgresql.org/search.mpl


pgsql-sql by date:

Previous
From: "J.Fernando Moyano"
Date:
Subject: cache lookup failed ???? What is it ???!!!
Next
From: Kristoff Bonne
Date:
Subject: Re: What is a "tuple"