Hi, Ken,
Ken Hill schrieb:
> I need some help with a bit of SQL. I have two tables. I want to find
> records in one table that don't match records in another table based on
> a common column in the two tables. Both tables have a column named
> 'key100'. I was trying something like:
>
> SELECT count(*)
> FROM table1, table2
> WHERE (table1.key100 != table2.key100);
>
> But the query is very slow and I finally just cancel it. Any help is
> very much appreciated.
Do you have indices on the key100 columns? Is autovacuum running, or do
you do analyze manually?
Can you send us the output from "EXPLAIN ANALYZE [your query]"?
Btw, I don't think this query will do what you wanted, it basically
creates a cross product, that means if your tables look like:
schabitest=# select * from table1;key100 | valuea | valueb
--------+--------+-------- 1 | foo | bar 2 | blah | blubb 3 | manga | mungo
schabitest=# select * from table2;key100 | valuec | valued
--------+--------+-------- 1 | monday | euro 2 | sunday | dollar 4 | friday | pounds
Then your query will produce something like:
schabitest=# select * from table1, table2 WHERE (table1.key100 !=
table2.key100);key100 | valuea | valueb | key100 | valuec | valued
--------+--------+--------+--------+--------+-------- 1 | foo | bar | 2 | sunday | dollar 1 | foo
|bar | 4 | friday | pounds 2 | blah | blubb | 1 | monday | euro 2 | blah | blubb | 4 |
friday| pounds 3 | manga | mungo | 1 | monday | euro 3 | manga | mungo | 2 | sunday | dollar
3| manga | mungo | 4 | friday | pounds
I suggest you would like to have all records from table1 that don't have
a corresponding record in table2:
schabitest=# select * from table1 where table1.key100 not in (select
key100 from table2);key100 | valuea | valueb
--------+--------+-------- 3 | manga | mungo
HTH,
Markus
