Finding matching columns from two tables - Mailing list pgsql-sql
From | Richard Emberson |
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Subject | Finding matching columns from two tables |
Date | |
Msg-id | 3C757613.84BA73EB@phc.net Whole thread Raw |
Responses |
Re: Finding matching columns from two tables
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List | pgsql-sql |
Below can be included in a psql via the \i command. There are basically two tables (and some others for ref-int): membership and group_sets. A user (user_id) is a member of one or more groups (group_id). Groups are also organized into group sets (group_set_id) in the group_sets table. The task is to find the group_set_id for a set of groups, if it exists, given a user_id, and the associated groups that user is a member of. The function, get_group_set_id(), at the end is my attempt. It works but its rather convoluted and requires 4 SELECT statements. Any help. Thanks. Richard ---------------------------------------------------------------- /* In some cases, the group_ids associated with a group_set_id are the same as the group_ids associated with a user_id. For a given user_id determine if there is a corresponding group_set_id. Find the group_set_id such that for a given user_id (input parameter) there is a one-to-one correspondence between the group_ids associated with the user_id and the group_ids associated with the group_set_id; for every group_id that the user_id has, the group_set_id also has it and for every group_id that the group_set_id has, the user_id also has it. If there is no such group_set_id, then return null. What query will generate the group_set_id? The function get_group_set_id() is my attempt. Is there a better way? The fact that it has 4 SELECT statement in it is, I expect, far from optimum. SELECT get_group_set_id(10); -- should be 30 SELECT get_group_set_id(11); -- should be -1 SELECT get_group_set_id(12); -- should be -1 SELECT get_group_set_id(13); -- should be 31 */ -- all of the users -- user_id are unique DROP TABLE users; CREATE TABLE users ( user_id BIGINT, -- other columns PRIMARY KEY (user_id) ); COPY users FROM stdin USING DELIMITERS ':'; 10 11 12 13 \. -- all of the groups -- user_id are unique DROP TABLE groups; CREATE TABLE groups ( group_id BIGINT, -- other columns PRIMARY KEY (group_id) ); COPY groups FROM stdin USING DELIMITERS ':'; 20 21 22 23 24 \. -- a user can be a member of one or more groups DROP TABLE membership; CREATE TABLE membership ( user_id BIGINT, group_id BIGINT, -- other columns FOREIGN KEY (user_id)REFERENCES users (user_id), FOREIGN KEY (group_id) REFERENCES groups (group_id) ); COPY membership FROM stdin USING DELIMITERS ':'; 10:20 10:21 11:20 12:21 12:22 12:23 13:20 13:22 \. -- a group set is a set of one or more groups DROP TABLE group_sets; CREATE TABLE group_sets ( group_set_id BIGINT, group_id BIGINT, -- other columns FOREIGN KEY (group_id)REFERENCES groups (group_id) -- FOREIGN KEY (group_set_id) REFERENCES group_sets (group_set_id) ); COPY group_sets FROM stdin USING DELIMITERS ':'; 30:20 30:21 31:20 31:22 32:20 32:21 32:22 32:24 \.CREATE OR REPLACE FUNCTION get_group_set_id ( BIGINT ) RETURNS BIGINT AS ' DECLARE -- parameters user_id_p ALIAS FOR $1; -- local variables group_id_count_v INTEGER; count_v INTEGER; group_set_id_vBIGINT; foo group_sets%ROWTYPE; BEGIN -- how many groups were given to this user SELECT INTO group_id_count_v count(*) FROM membership WHERE user_id= user_id_p; -- select all that have groups shared by the linked user and -- have the right number (or more) FOR foo IN SELECTgroup_set_id FROM group_sets WHERE group_id IN (SELECT group_id FROM membership WHERE user_id= user_id_p) GROUP BY group_set_id HAVING count(*) = group_id_count_v LOOP -- make sure it has only the right number of group_ids SELECT INTO count_v count(*) FROM group_sets WHERE group_set_id = foo.group_set_id; IF group_id_count_v = count_v THEN RETURN foo.group_set_id; END IF; END LOOP; RETURN -1; END; ' LANGUAGE 'plpgsql'; ----------------------------------------------------------------