On Tue, Jun 16, 2009 at 2:39 PM, Gavin Baumanis<gavinb@eclinic.com.au> wrote:
> At the risk of being wrong.... (I'm always ready to learn something new) -
> and seemingly I'm only too happy to be wrong!...
>
> And... it might even be that it is exactly the same result - but I would
> have proposed;
>
> SELECT
> R.region_name,
> Count(*) AS RegionComplaints
> FROM
> Region AS R
> LEFT JOIN City AS Ci
> LEFT JOIN Complaint AS Cm ON Ci.id = Cm.city_id
> ON R.id = C.region_id
> GROUP BY
> R.region_name;
Yup, it produces the same result.
--
Regards,
Richard Broersma Jr.
Visit the Los Angeles PostgreSQL Users Group (LAPUG)
http://pugs.postgresql.org/lapug
