These seems to work, thx... :)
BTJ
On Fri, 16 Feb 2007 09:23:44 -0600
"Adam Rich" <adam.r@sbcglobal.net> wrote:
>
> Or, if you need the whole row:
>
> SELECT at1.* FROM a_table as at1
> WHERE EXISTS (
> SELECT 1 FROM a_table as at2
> WHERE at2.my_date = at1.my_date
> AND at2.prod_id = at1.prod_id
> AND at2.primary_key <> at1.primary_key
> )
>
> This form can easily be adjusted to show
> only certain duplicates, or only to delete
> certain duplicates.
>
>
> -----Original Message-----
> From: pgsql-general-owner@postgresql.org
> [mailto:pgsql-general-owner@postgresql.org] On Behalf Of Ron Johnson
> Sent: Friday, February 16, 2007 9:13 AM
> To: pgsql-general@postgresql.org
> Subject: Re: [GENERAL] Problem writing sql statement....
>
>
> -----BEGIN PGP SIGNED MESSAGE-----
> Hash: SHA1
>
> On 02/16/07 01:44, Bjørn T Johansen wrote:
> > Not exactly what I want... I don't know the date or id, I just
> > need to find all rows that have the same date and the same id..
>
> SELECT SOME_DATE, PRODUCTIONID, COUNT(*)
> FROM A_TABLE
> GROUP BY SOME_DATE, PRODUCTIONID
> HAVING COUNT(*) > 1;
>
>
> >
> > BTJ
> >
> > On Thu, 15 Feb 2007 16:46:21 -0600
> > Ron Johnson <ron.l.johnson@cox.net> wrote:
> >
> > On 02/15/07 15:13, Bjørn T Johansen wrote:
> >>>> I have a table that I want to find rows that have the same value
> >>>> in two fields, e.g. all rows that have the same date and also the
> >>>> same productionid... How do I write such an sql statement?
> > If I understand your question:
> >
> > SELECT FIELD_1, FIELD_2, COUNT(*)
> > FROM A_TABLE
> > WHERE SOME_DATE = 'yyyy-mm-dd'
> > AND PRODUCTIONID = nnnn
> > GROUP BY FIELD_1, FIELD_2
> > HAVING COUNT(*) > 1;
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> JF4XWsS68ru0jsNaQjvHo20=
> =AKKx
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