Or, if you need the whole row:
SELECT at1.* FROM a_table as at1
WHERE EXISTS (
SELECT 1 FROM a_table as at2
WHERE at2.my_date = at1.my_date
AND at2.prod_id = at1.prod_id
AND at2.primary_key <> at1.primary_key
)
This form can easily be adjusted to show
only certain duplicates, or only to delete
certain duplicates.
-----Original Message-----
From: pgsql-general-owner@postgresql.org
[mailto:pgsql-general-owner@postgresql.org] On Behalf Of Ron Johnson
Sent: Friday, February 16, 2007 9:13 AM
To: pgsql-general@postgresql.org
Subject: Re: [GENERAL] Problem writing sql statement....
-----BEGIN PGP SIGNED MESSAGE-----
Hash: SHA1
On 02/16/07 01:44, Bjørn T Johansen wrote:
> Not exactly what I want... I don't know the date or id, I just
> need to find all rows that have the same date and the same id..
SELECT SOME_DATE, PRODUCTIONID, COUNT(*)
FROM A_TABLE
GROUP BY SOME_DATE, PRODUCTIONID
HAVING COUNT(*) > 1;
>
> BTJ
>
> On Thu, 15 Feb 2007 16:46:21 -0600
> Ron Johnson <ron.l.johnson@cox.net> wrote:
>
> On 02/15/07 15:13, Bjørn T Johansen wrote:
>>>> I have a table that I want to find rows that have the same value
>>>> in two fields, e.g. all rows that have the same date and also the
>>>> same productionid... How do I write such an sql statement?
> If I understand your question:
>
> SELECT FIELD_1, FIELD_2, COUNT(*)
> FROM A_TABLE
> WHERE SOME_DATE = 'yyyy-mm-dd'
> AND PRODUCTIONID = nnnn
> GROUP BY FIELD_1, FIELD_2
> HAVING COUNT(*) > 1;
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