-----BEGIN PGP SIGNED MESSAGE-----
Hash: SHA1
On 02/16/07 01:44, Bjørn T Johansen wrote:
> Not exactly what I want... I don't know the date or id, I just
> need to find all rows that have the same date and the same id..
SELECT SOME_DATE, PRODUCTIONID, COUNT(*)
FROM A_TABLE
GROUP BY SOME_DATE, PRODUCTIONID
HAVING COUNT(*) > 1;
>
> BTJ
>
> On Thu, 15 Feb 2007 16:46:21 -0600
> Ron Johnson <ron.l.johnson@cox.net> wrote:
>
> On 02/15/07 15:13, Bjørn T Johansen wrote:
>>>> I have a table that I want to find rows that have the same value
>>>> in two fields, e.g. all rows that have the same date and also the
>>>> same productionid... How do I write such an sql statement?
> If I understand your question:
>
> SELECT FIELD_1, FIELD_2, COUNT(*)
> FROM A_TABLE
> WHERE SOME_DATE = 'yyyy-mm-dd'
> AND PRODUCTIONID = nnnn
> GROUP BY FIELD_1, FIELD_2
> HAVING COUNT(*) > 1;
-----BEGIN PGP SIGNATURE-----
Version: GnuPG v1.4.6 (GNU/Linux)
iD8DBQFF1coSS9HxQb37XmcRAlj5AJ94KSt0BCWwFehMNha4Ljf/Cr0tDQCg6AZN
JF4XWsS68ru0jsNaQjvHo20=
=AKKx
-----END PGP SIGNATURE-----
