On Wednesday 31 January 2007 8:46 pm, Harvey, Allan AC wrote:
> I know the function is there.
> What am I doing wrong?
>
> galvdb=#
> galvdb=# \df+ delete_old
> List of functions
> Result data type | Schema | Name | Argument data types | Owner | Language
> | Source code | Description
> ------------------+--------+------+---------------------+-------+----------
>+-------------+------------- (0 rows)
>
> galvdb=# select delete_old();
> delete_old
> ------------
> 482
> (1 row)
>
> galvdb=# select version();
> version
> ---------------------------------------------------------------------------
>---------- PostgreSQL 8.2.0 on i686-pc-linux-gnu, compiled by GCC gcc (GCC)
> 3.3.3 (SuSE Linux) (1 row)
>
> galvdb=#
>
>
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My guess is it is a permissions issue. The user you are logged in does not
have the privileges necessary to view the function. By default functions have
EXECUTE privileges granted to the ROLE PUBLIC which would explain you being
able to do select delete_old(). See below for more information.
http://www.postgresql.org/docs/8.2/interactive/sql-grant.html
--
Adrian Klaver
aklaver@comcast.net
