Mathieu,
> SELECT date_trunc('month', f.date_creation) as mois,
> sum(f.montant_ttc / d.taux) as facture,
> (SELECT sum(f2.montant_ttc / d2.taux) as facture2
> FROM facture AS f2 JOIN devise AS d2 USING (id_devise)
> WHERE date_trunc('month', f2.date_creation)
> <= date_trunc('month', f.date_creation))
> FROM facture AS f JOIN devise AS d USING (id_devise)
> GROUP BY date_trunc('month', f.date_creation)
> "Sub-SELECT uses un-GROUPed attribute f.date_creation from outer query"
> Which is not really true, but some way is...
Hmmm ... this looks like a minor parser bug. What Postgres version are you
using?
> What I want is to get the sum of the month, and the sum of the month and
> the previous.
>
> If someone has a clue, something, anything... :)
Sure. Try putting the sub-select in the FROM clause, instead of the SELECT;
that should un-confuse the parser about the grouping.
--
Josh Berkus
Aglio Database Solutions
San Francisco
