Hi there,
I think I need to explain a bit further.
I tried simply using
update people
replace(address, 'mailto:','');
but unfortunately that produced a duplicate key error as some of the
addresses prefixed with 'mailto:' are already present (unprefixed) in
the table.
So what I need to do is find those entries - those items in the table
for which there is an equivalent entry prefixed with 'mailto:'.
Sorry if I'm not being very clear!
Cheers
BBB
John Sidney-Woollett wrote:
> Do you mean?
>
> select replace(address, 'mailto:', '') from people
>
> ... and if you only want to find the ones that start with "mailto:"
>
> select replace(address, 'mailto:', '') from people
> where address like 'mailto:%'
>
> John
>
> badlydrawnbhoy wrote:
> > Hi all,
> >
> > I hope this is the right forum for this, but please correct me if
> > somewhere else is more appropriate.
> >
> > I need to locate all the entries in a table that match , but only after
> > a number of characters have been ignored. I have a table of email
> > addresses, and someone else has erroneously entered some addresses
> > prefixed with 'mailto:', which I'd like to ignore.
> >
> > An example would be: john.smith@smiths.com should match
> > mailto:john.smith@smiths.com
> >
> > I've tried the following
> >
> > select address
> > from people
> > where address = (select replace(address, 'mailto:', '') from people);
> >
> > which gives me the error
> >
> > ERROR: more than one row returned by a subquery used as an expression
> >
> > I'm running on PostgreSQL 7.4.7
> >
> > Thanks in advance,
> >
> > BBB
> >
> >
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