Do you mean?
select replace(address, 'mailto:', '') from people
... and if you only want to find the ones that start with "mailto:"
select replace(address, 'mailto:', '') from people
where address like 'mailto:%'
John
badlydrawnbhoy wrote:
> Hi all,
>
> I hope this is the right forum for this, but please correct me if
> somewhere else is more appropriate.
>
> I need to locate all the entries in a table that match , but only after
> a number of characters have been ignored. I have a table of email
> addresses, and someone else has erroneously entered some addresses
> prefixed with 'mailto:', which I'd like to ignore.
>
> An example would be: john.smith@smiths.com should match
> mailto:john.smith@smiths.com
>
> I've tried the following
>
> select address
> from people
> where address = (select replace(address, 'mailto:', '') from people);
>
> which gives me the error
>
> ERROR: more than one row returned by a subquery used as an expression
>
> I'm running on PostgreSQL 7.4.7
>
> Thanks in advance,
>
> BBB
>
>
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