Thread: Re: Restrict publishing of partitioned table with a foreign table as partition
Re: Restrict publishing of partitioned table with a foreign table as partition
From
Álvaro Herrera
Date:
Hello, I think reimplementing list_member_oid() under a different name (is_ancestor_member_relids) is pointless and should not be done. It also appears to me that we haven't nailed the error messages just yet. I tried to fix it upthread, but didn't really get it correct. For instance, consider this case taken from the new regression tests: /* test setup */ CREATE SCHEMA sch3; CREATE TABLE sch3.tmain(id int) PARTITION BY RANGE(id); CREATE TABLE sch3.part1 PARTITION OF sch3.tmain FOR VALUES FROM (0) TO (5); CREATE TABLE sch3.part2(id int) PARTITION BY RANGE(id); CREATE FOREIGN TABLE sch3.part2_1 PARTITION OF sch3.part2 FOR VALUES FROM (5) TO (10) SERVER fdw_server; ALTER TABLE sch3.tmain ATTACH PARTITION sch3.part2 FOR VALUES FROM (5) TO (10); The issue occurs in the next command: CREATE PUBLICATION pub1 FOR TABLE sch3.tmain WITH (publish_via_partition_root); ERROR: cannot add partitioned table "tmain" to publication "pub1", which has "publish_via_partition_root" set to "true" DETAIL: The table contains a partition that's a foreign table. The user is trying to create a publication, so an error saying that it's not possible to add a partition is a bit off-point. (If you squint hard enough it sort of makes sense, but it seems inconsistent enough.) We could replace the word "add" with the word "include" there and this particular problem would be fixed, perhaps. However, the next one is worse: CREATE PUBLICATION pub1 FOR ALL TABLES WITH (publish_via_partition_root); ERROR: cannot set parameter "publish_via_partition_root" to "true" for publication "pub1" DETAIL: Published partitioned table "tmain" contains a partition that is a foreign table. Here we again try to create a publication, but we get an error that we cannot set the parameter, which is even more detached from reality. Maybe what we need is to add another parameter to that function to indicate which operation is being executed (create publication, add schema, change the parameter), which is used to indicate the error message to throw. With that thought in mind, I think it would make things simpler for us to remove the duplicate copies of the same error messages by adding yet another function, after publication_check_foreign_parts(), which receives the operation being executed and whatever additional parameter it needs, and throws the error. If publication_check_foreign_parts() also receives the operation being executed, it can simply pass it through to that new function when an error needs to be thrown; other places that hardcode error situations would pass a constant for the operation. But the non-idiomatic locking of pg_partitioned_table appears to continue to be the pain point of this patch. My impression is that using a lock is the wrong approach to solve the concurrency problem. Maybe we can use a ConditionVariable instead somehow. (The real trick here is to figure out exactly _how_ to use the CV, I mean what exactly is the condition that the CV sleeps on?) -- Álvaro Herrera 48°01'N 7°57'E — https://www.EnterpriseDB.com/ "Industry suffers from the managerial dogma that for the sake of stability and continuity, the company should be independent of the competence of individual employees." (E. Dijkstra)
Re: Restrict publishing of partitioned table with a foreign table as partition
From
Amit Kapila
Date:
On Sun, May 11, 2025 at 6:53 AM Álvaro Herrera <alvherre@alvh.no-ip.org> wrote: > > But the non-idiomatic locking of pg_partitioned_table appears to > continue to be the pain point of this patch. My impression is that > using a lock is the wrong approach to solve the concurrency problem. > Maybe we can use a ConditionVariable instead somehow. (The real trick > here is to figure out exactly _how_ to use the CV, I mean what exactly > is the condition that the CV sleeps on?) > Can we fix this problem by having a check at the time of CREATESUBSCRIPTION such that, if copy-data is true, then we ensure that the specified publishers don't have a foreign table? We have a somewhat similar check for publications in the function check_publications_origin(), though for a different purpose. Along with it, we can still have a check during foreign table creation/attach that it doesn't become part of some publication, as the patch may have it now. -- With Regards, Amit Kapila.
Re: Restrict publishing of partitioned table with a foreign table as partition
From
Ajin Cherian
Date:
On Tue, May 20, 2025 at 2:33 AM Shlok Kyal <shlok.kyal.oss@gmail.com> wrote: > > This approach seems better to me. I have created a patch with the > above approach. > > Thanks and Regards, > Shlok Kyal Some quick comments on the patch: 1. In doc/src/sgml/ref/create_subscription.sgml: + has partitioned table with foreign table as partition. If this scenario is + detected we ERROR is logged to the user. + </para> + Should be: "If this scenario is detected an ERROR is logged to the user." (remove "we"). In src/backend/commands/subscriptioncmds.c: 2. The comment header: + * This function is in charge of detecting if publisher with + * publish_via_partition_root=true publishes a partitioned table that has a + * foreign table as a partition. Add "and throw an error if found" at the end of that sentence to correctly describe what the function does. 3. + appendStringInfoString(&cmd, + "SELECT DISTINCT P.pubname AS pubname " + "from pg_catalog.pg_publication p, LATERAL " + "pg_get_publication_tables(p.pubname) gpt, LATERAL " + "pg_partition_tree(gpt.relid) gt JOIN pg_catalog.pg_foreign_table ft ON " + "ft.ftrelid = gt.relid WHERE p.pubviaroot = true AND p.pubname IN ("); use FROM rather than from to maintain SQL style consistency. 4. + errdetail_plural("The subscription being created on a publication (%s) with publish_via_root_partition = true and contains partitioned tables with foreign table as partition ", + "The subscription being created on publications (%s) with publish_via_root_partition = true and contains partitioned tables with foreign table as partition ", + list_length(publist), pubnames->data), I think you meant "publish_via_partition_root" here and not "publish_via_root_partition ". regards, Ajin Cherian Fujitsu Australia