Thread: Re: Strange behaviors with ranges

Re: Strange behaviors with ranges

From
Paul Jungwirth
Date:
On 8/27/24 10:29, Jean-Christophe Boggio wrote:
> I have 2 very confusing behaviors when using ranges.
> 
> It all started with this query:
> 
>      WITH rangespaliers AS (
>          SELECT numrange( qtep1+1   , qtep2,  '[]') AS rangep FROM paliers JOIN tmp_limitcontrats 
> USING(idcontrat)
> --        SELECT numrange( qtep1+1   , qtep2,  '[]') AS rangep FROM paliers WHERE idcontrat=1003
>      )
>      ,rangespaliers2 AS (
>          select *
>          FROM rangespaliers
>          WHERE rangep <> NUMRANGE(NULL, NULL) -- ERROR IS HERE
>      )
>      select * from rangespaliers2;
> 
> When I run this query, I get the error "Range lower bound must be less than or equal to range upper 
> bound".
> 
> (a) If I comment out the line marked "ERROR IS HERE", I don't have an error (but I'm missing the 
> filter of course).
> 
> (b) Also, if I uncomment line 3 and comment out line 2, I get the correct behavior. Very strange 
> thing is that tmp_limitcontrats has only one row which contains "idcontrat=1003".

The issue is the order-of-operations used by the planner. If I put EXPLAIN on your last query, I see:

  Hash Join  (cost=16.64..109.90 rows=2410 width=64)
    Hash Cond: (tmp_limitcontrats.idcontrat = paliers.idcontrat)
    ->  Seq Scan on tmp_limitcontrats  (cost=0.00..35.50 rows=2550 width=4)
    ->  Hash  (cost=14.27..14.27 rows=189 width=12)
          ->  Seq Scan on paliers  (cost=0.00..14.27 rows=189 width=12)
                Filter: (numrange(((qtep1 + 1))::numeric, (qtep2)::numeric) <> '(,)'::numrange)

So we are applying that filter to every row in paliers, not just the one with idcontrat = 1003.

Indeed this simplified version also fails:

SELECT numrange(qtep1+1,qtep2) as rangep FROM paliers;

Yours,

-- 
Paul              ~{:-)
pj@illuminatedcomputing.com



Re: Strange behaviors with ranges

From
Jean-Christophe BOGGIO
Date:
Paul,

Le 27/08/2024 à 20:11, Paul Jungwirth a écrit :
> The issue is the order-of-operations used by the planner. If I put 
> EXPLAIN on your last query, I see:
>
>  Hash Join  (cost=16.64..109.90 rows=2410 width=64)
>    Hash Cond: (tmp_limitcontrats.idcontrat = paliers.idcontrat)
>    ->  Seq Scan on tmp_limitcontrats  (cost=0.00..35.50 rows=2550 
> width=4)
>    ->  Hash  (cost=14.27..14.27 rows=189 width=12)
>          ->  Seq Scan on paliers  (cost=0.00..14.27 rows=189 width=12)
>                Filter: (numrange(((qtep1 + 1))::numeric, 
> (qtep2)::numeric) <> '(,)'::numrange)
>
> So we are applying that filter to every row in paliers, not just the 
> one with idcontrat = 1003.

I understand, makes perfect sense. Thanks for the explanation. Have a 
nice day,