Thread: join plan with unexpected var clauses
Hi, At a customer we came across a curious plan (see attached testcase). Given the testcase we see that the outer semi join tries to join the outer with the inner table id columns, even though the middle table id column is also there. Is this expected behavior? The reason i'm asking is two-fold: - the inner hash table now is bigger than i'd expect and has columns that you would normally not select on. - the middle join now projects the inner as result, which is quite suprising and seems invalid from a SQL standpoint. Plan: Finalize Aggregate Output: count(*) -> Gather Output: (PARTIAL count(*)) Workers Planned: 4 -> Partial Aggregate Output: PARTIAL count(*) -> Parallel Hash Semi Join Hash Cond: (_outer.id3 = _inner.id2) -> Parallel Seq Scan on public._outer Output: _outer.id3, _outer.extra1 -> Parallel Hash Output: middle.id1, _inner.id2 -> Parallel Hash Semi Join Output: middle.id1, _inner.id2 Hash Cond: (middle.id1 = _inner.id2) -> Parallel Seq Scan on public.middle Output: middle.id1 -> Parallel Hash Output: _inner.id2 -> Parallel Seq Scan on public._inner Output: _inner.id2 Kind regards, Luc Swarm64
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Luc Vlaming <luc@swarm64.com> writes: > Given the testcase we see that the outer semi join tries to join the > outer with the inner table id columns, even though the middle table id > column is also there. Is this expected behavior? I don't see anything greatly wrong with it. The planner has concluded that _inner.id2 and middle.id1 are part of an equivalence class, so it can form the top-level join by equating _outer.id3 to either of them. AFAIR that choice is made at random --- there's certainly not any logic that thinks about "well, the intermediate join output could be a bit narrower if we choose this one instead of that one". I think "made at random" actually boils down to "take the first usable member of the equivalence class". If I switch around the wording of the first equality condition: ... select 1 from _inner where middle.id1 = _inner.id2 then I get a plan where the top join uses middle.id1. However, it's still propagating both middle.id1 and _inner.id2 up through the bottom join, so that isn't buying anything efficiency-wise. regards, tom lane