Thread: left outer join to pull in most recent record
I have the following stock list table. # select * from stock; s_stock_no | s_regno ------------+--------- N12345 | GPS1 N12346 | TEST1 U123 | GPS1 (3 rows) This shows two vehicles. GPS1 was originally a new vehicle which we then sold. TEST1 is also a new vehicle GPS1 is sunsequently purchased back from the customer as a part exchange, and is put on the stock table as a used car. If I later want to do a search based on the registration number, wishing to retrieve the most recent record what is the *best* (quickest or least CPU time depending on your preference) way to do this? By most recent record, I mean the record with the highest stock number. I'm looking for a solution to do a straight select where..... but I am also looking for a solution that can be used in a left join, for example select diary.*, stock.* from diary left outer join stock on ...........
select distinct s_regno, max(s_stock_no) over (partition by s_regno order by s_regno) from stock;
Am 09.10.2018 um 15:18 schrieb Gary Stainburn:
I have the following stock list table. # select * from stock;s_stock_no | s_regno ------------+---------N12345 | GPS1N12346 | TEST1U123 | GPS1 (3 rows) This shows two vehicles. GPS1 was originally a new vehicle which we then sold. TEST1 is also a new vehicle GPS1 is sunsequently purchased back from the customer as a part exchange, and is put on the stock table as a used car. If I later want to do a search based on the registration number, wishing to retrieve the most recent record what is the *best* (quickest or least CPU time depending on your preference) way to do this? By most recent record, I mean the record with the highest stock number. I'm looking for a solution to do a straight select where..... but I am also looking for a solution that can be used in a left join, for example select diary.*, stock.* from diaryleft outer join stock on ...........
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