Thread: Intersection of two date interval
Hi,<br /><br />How can i find the number of days in the intersection of 2 date interval?<br />For example: <br />1st interval:(10.01.2007, 20.01.2007)<br />2nd interval: (13.01.2007, 21.01.2007)<br />The intersection dates are: 13,14,15,16,17,18,19,20 <br />The result is: 8<br /><br />How can i find the result, 8 in an sql query without using CASEstatements?<br /><br />Table columns are id PK, date1 date, date2 date.<br /><br />Thanks for all your help.<br /><brclear="all" /><br />Suha<br /><br /><br />
am Fri, dem 26.01.2007, um 11:39:03 +0200 mailte Suha Onay folgendes:
> Hi,
>
> How can i find the number of days in the intersection of 2 date interval?
> For example:
> 1st interval: (10.01.2007, 20.01.2007)
> 2nd interval: (13.01.2007, 21.01.2007)
> The intersection dates are: 13,14,15,16,17,18,19, 20
> The result is: 8
>
> How can i find the result, 8 in an sql query without using CASE statements?
Some time ago i wrote a function for this, i hope it's helpfull for you:
(not realy tested, be careful!)
create type start_end as (t1 timestamptz, t2 timestamptz);
create or replace function time_intersect (timestamptz, timestamptz, timestamptz, timestamptz) returns start_end as $$
declare _s1 alias for $1; _e1 alias for $2; _s2 alias for $3; _e2 alias for $4;
_start timestamptz; _end timestamptz; _return start_end;
begin
if _s1 < _s2 then _start := _s2; else _start := _s1; end if;
if _e1 < _e2 then _end := _e1; else _end := _e2; end if;
if _start < _end then _return.t1 := _start; _return.t2 := _end; else
_return.t1 := NULL; _return.t2 := NULL; end if;
return _return;
end
$$ language plpgsql;
test=# set datestyle=german;
SET
test=*# select time_intersect('10.01.2007'::date, '20.01.2007'::date, '13.01.2007'::date, '21.01.2007'::date);
time_intersect
-------------------------------------------------------("13.01.2007 00:00:00 CET","20.01.2007 00:00:00 CET")
(1 row)
test=*# select *, t2-t1 from time_intersect('10.01.2007'::date, '20.01.2007'::date, '13.01.2007'::date,
'21.01.2007'::date); t1 | t2 | ?column?
-------------------------+-------------------------+----------13.01.2007 00:00:00 CET | 20.01.2007 00:00:00 CET | @ 7
days
(1 row)
Andreas
--
Andreas Kretschmer
Kontakt: Heynitz: 035242/47150, D1: 0160/7141639 (mehr: -> Header)
GnuPG-ID: 0x3FFF606C, privat 0x7F4584DA http://wwwkeys.de.pgp.net
Στις Παρασκευή 26 Ιανουάριος 2007 11:50, ο/η A. Kretschmer έγραψε:
> am Fri, dem 26.01.2007, um 11:39:03 +0200 mailte Suha Onay folgendes:
> > Hi,
> >
> > How can i find the number of days in the intersection of 2 date interval?
> > For example:
> > 1st interval: (10.01.2007, 20.01.2007)
> > 2nd interval: (13.01.2007, 21.01.2007)
> > The intersection dates are: 13,14,15,16,17,18,19, 20
> > The result is: 8
> >
> > How can i find the result, 8 in an sql query without using CASE
> > statements?
>
> Some time ago i wrote a function for this, i hope it's helpfull for you:
> (not realy tested, be careful!)
>
>
>
> create type start_end as (t1 timestamptz, t2 timestamptz);
>
> create or replace function time_intersect (timestamptz, timestamptz,
> timestamptz, timestamptz) returns start_end as $$ declare
> _s1 alias for $1;
> _e1 alias for $2;
> _s2 alias for $3;
> _e2 alias for $4;
> _start timestamptz;
> _end timestamptz;
> _return start_end;
> begin
>
> if _s1 < _s2 then
> _start := _s2;
> else
> _start := _s1;
> end if;
>
> if _e1 < _e2 then
> _end := _e1;
> else
> _end := _e2;
> end if;
>
> if _start < _end then
> _return.t1 := _start;
> _return.t2 := _end;
> else
> _return.t1 := NULL;
> _return.t2 := NULL;
> end if;
>
> return _return;
> end
> $$ language plpgsql;
>
>
Suha,
the function is the number of days in the
maximum of the two start dates , untill , minimum of the two end dates
interval.
But in postgresql (7.4.15 at least) there is no MIN(date,date),MAX(date,date)
functions. So someone has to write them, so you cant avoid some logic there.
Whats your problem with "CASE" statements?
what you are basically looking for is smth like the above implementation
from Andreas.
> test=# set datestyle=german;
> SET
> test=*# select time_intersect('10.01.2007'::date, '20.01.2007'::date,
> '13.01.2007'::date, '21.01.2007'::date); time_intersect
> -------------------------------------------------------
> ("13.01.2007 00:00:00 CET","20.01.2007 00:00:00 CET")
> (1 row)
>
>
> test=*# select *, t2-t1 from time_intersect('10.01.2007'::date,
> '20.01.2007'::date, '13.01.2007'::date, '21.01.2007'::date); t1
> | t2 | ?column?
> -------------------------+-------------------------+----------
> 13.01.2007 00:00:00 CET | 20.01.2007 00:00:00 CET | @ 7 days
> (1 row)
>
>
>
>
> Andreas
--
Achilleas Mantzios
On Fri, Jan 26, 2007 at 12:02:24 +0200, Achilleas Mantzios <achill@matrix.gatewaynet.com> wrote:
> Suha,
> the function is the number of days in the
> maximum of the two start dates , untill , minimum of the two end dates
> interval.
> But in postgresql (7.4.15 at least) there is no MIN(date,date),MAX(date,date)
> functions. So someone has to write them, so you cant avoid some logic there.
> Whats your problem with "CASE" statements?
> what you are basically looking for is smth like the above implementation
> from Andreas.
Postgres (at least since 8.1) has GREATEST and LEAST and they provide the
needed functions.
And you should be able to subtract two dates (not timestamps) to get an
integer. (And to count the number of days rather than the time between, you
need to add 1.)
You also will want to put a floor on the overlap so that you don't get
negative values.
So in your case the query would look something like:
bruno=> SELECT GREATEST(0, LEAST('2007-01-20'::date, '2007-01-21'::date) -
bruno(> GREATEST('2007-01-10'::date, '2007-01-13'::date) + 1);greatest
---------- 8
(1 row)