Thread: How to call table returning function with other table

Hi.

I have a function that is defined like (which works, sorry for the 
pseudocode)
create type xxx as (id,...);
create function calcuate_xxx (integer) returns xxx as $$ select $1, 
(select sum(amount) from bigtable where something) as a, (select 
sum(amount) from bigtable where some-other-thing) as b $$ language sql 
stable;

What I cannot figure out is, if I have another query that returns a 
single column of those id's, how do I get a table back with the function 
applied to all ids (hence multiple rows).

So it is something like "select xxx(id) from othertable where otherwhere 
= 't'" except that it mangles the columns into an array. I have tried to 
move the function-call into the fromlist (as it is usually done) but I 
seem unsuccessful in getting the ID's into it.

Thanks in advance

Svenne

2006/3/19, Svenne Krap <svenne@krap.dk>:

> So it is something like "select xxx(id) from othertable where otherwhere
> = 't'" except that it mangles the columns into an array. I have tried to
> move the function-call into the fromlist (as it is usually done) but I
> seem unsuccessful in getting the ID's into it.

You have to use something like SELECT (xxx(id)).* FROM othertable
WHERE otherwhere = 't', I believe.

Markus Bertheau

Perfect. Thanks.<br /><br /> Svenne<br /><br /> Markus Bertheau wrote: <blockquote
cite="mid684362e10603190532p1903fca8p@mail.gmail.com"type="cite"><pre wrap="">2006/3/19, Svenne Krap <a
class="moz-txt-link-rfc2396E"href="mailto:svenne@krap.dk"><svenne@krap.dk></a>:
 
 </pre><blockquote type="cite"><pre wrap="">So it is something like "select xxx(id) from othertable where otherwhere
= 't'" except that it mangles the columns into an array. I have tried to
move the function-call into the fromlist (as it is usually done) but I
seem unsuccessful in getting the ID's into it.   </pre></blockquote><pre wrap="">
You have to use something like SELECT (xxx(id)).* FROM othertable
WHERE otherwhere = 't', I believe.

Markus Bertheau

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