Thread: Returning Multiple Values from CASE statement?
Hello,
This is probably an odd request, but I have my reasons :) Basically, what I need to do is return *multiple* values each for a number of criteria. Imagine being able to return multiple values for each CASE statement... that's what I'm trying to do. I can solve this with subqueries, but as you'll see it's *really* ugly, and I'm sure there's a better way (performance is key). The other way obviously is to repeat the CASE statement for each value I want to return.... but that seems inefficient also. So I was wondering if someone could take a look at my query and slap me up side the head and set me straight?
Here's the kind of query that would *like* to be able to do.....
select
(case when column1 = column2 then column5,column6) as alias5,alias6,
(case when column3 = column4 then column7,column8) as alias7,alias8
from
mytable
;
(case when column1 = column2 then column5,column6) as alias5,alias6,
(case when column3 = column4 then column7,column8) as alias7,alias8
from
mytable
;
and here's the only ugly way I know how to do it......
select
a.*,
(case a.alias2 = true then b.column5) as alias5,
(case a.alias2 = true then b.column6) as alias6,
(case a.alias4 = true then b.column7) as alias7,
(case a.alias4 = true then b.column8) as alias8
from
(select
(case when column1 = column2 then true else false end) as alias2,
(case when column3 = column4 then true else false end) as alias4
from
mytable) a,
mytable b
where
a.id = b.id
;
a.*,
(case a.alias2 = true then b.column5) as alias5,
(case a.alias2 = true then b.column6) as alias6,
(case a.alias4 = true then b.column7) as alias7,
(case a.alias4 = true then b.column8) as alias8
from
(select
(case when column1 = column2 then true else false end) as alias2,
(case when column3 = column4 then true else false end) as alias4
from
mytable) a,
mytable b
where
a.id = b.id
;
Thanks!!
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