Thread: POSTGRESQL and PERL?

POSTGRESQL and PERL?

From
Peter Landis
Date:
Hi-  I'm a newbie at postgresql and was working on
sorting by category.  What my question is, how do you
sort by category when using a variable.  For instance,
you can sort by name in perl by doing:
$sqh = $dbh->prepare(q{select name from company order
by name;});
$sqh->execute();

but what if you have a variable set like:
$sort_selection = "name";

How do you sort by the variable?

For instance you cannot do:
$sqh = $dbh->prepare(q{select name from company order
by ?;});
$sqh->execute($sort_selection);

OR

$sqh = $dbh->prepare(q{select name from company order
by $sort_selection;});
$sqh->execute();

If anyone could help, I would greatly appreciate it.

Thanks again!



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RE: POSTGRESQL and PERL?

From
"Wallingford, Ted"
Date:
Peter my guess is you can just substitute the variable name in for the
actual sortfield name..

select * from company order by $field;

That's why variables BEGIN with denotation characters in Perl rather than
ending with them (like in basic)..

Anyway, let me know if that works... and which module are you using to hit
PostgreSQL????

thax,
Ted

_________________________________________________
Ted Wallingford
Manager of Information Technology
Independence Excavating, Inc.
Precision Environmental Co.
Independence Communications, Inc.
www.indexc.com


> -----Original Message-----
> From: Peter Landis [mailto:ntwebdeveloper@yahoo.com]
> Sent: Friday, May 26, 2000 11:58 AM
> To: pgsql-sql@postgresql.org
> Cc: pgsql-sql@postgresql.org
> Subject: [SQL] POSTGRESQL and PERL?
>
>
>
> Hi-
>    I'm a newbie at postgresql and was working on
> sorting by category.  What my question is, how do you
> sort by category when using a variable.  For instance,
> you can sort by name in perl by doing:
>
> $sqh = $dbh->prepare(q{select name from company order
> by name;});
> $sqh->execute();
>
> but what if you have a variable set like:
> $sort_selection = "name";
>
> How do you sort by the variable?
>
> For instance you cannot do:
> $sqh = $dbh->prepare(q{select name from company order
> by ?;});
> $sqh->execute($sort_selection);
>
> OR
>
> $sqh = $dbh->prepare(q{select name from company order
> by $sort_selection;});
> $sqh->execute();
>
> If anyone could help, I would greatly appreciate it.
>
> Thanks again!
>
>
>
> __________________________________________________
> Do You Yahoo!?
> Kick off your party with Yahoo! Invites.
> http://invites.yahoo.com/
>


Attachment

Re: POSTGRESQL and PERL?

From
Ed Loehr
Date:
Peter Landis wrote:
> 
> but what if you have a variable set like:
> $sort_selection = "name";
> 
> How do you sort by the variable?
> 
> For instance you cannot do...
> $sqh = $dbh->prepare(q{select name from company order
> by $sort_selection;});

Why not?  The query string is created before prepare is called...

Regards,
Ed Loehr


Re: POSTGRESQL and PERL?

From
"Richard Huxton"
Date:
----- Original Message -----
From: Ed Loehr <eloehr@austin.rr.com>
To: Peter Landis <ntwebdeveloper@yahoo.com>
Cc: <pgsql-sql@postgresql.org>
Sent: Friday, May 26, 2000 5:35 PM
Subject: Re: [SQL] POSTGRESQL and PERL?


> Peter Landis wrote:
> >
> > but what if you have a variable set like:
> > $sort_selection = "name";
> >
> > How do you sort by the variable?
> >
> > For instance you cannot do...
> > $sqh = $dbh->prepare(q{select name from company order
> > by $sort_selection;});
>
> Why not?  The query string is created before prepare is called...
>
I think you need qq{select ...} to indicate double-quoting "" or the
variable won't be substituted.

- Richard Huxton