OK DeJuan, but, probably your field's type is datetime and my type is
date. If I use your statement, I receive the following message:
ERROR: No such function 'date_in' with the specified attributes
By the way, I'm using the statement:
SELECT * FROM calls WHERE date_in>='$month-01-$year' AND
date_in<='$month-31-$year' ORDER BY employee_nbr, date_in
And it works fine.
Thanks,
Paulo K
"Jackson, DeJuan" wrote:
>
> template1=> select date_trunc('month', now());
> date_trunc
> ----------------------------
> Wed Sep 01 00:00:00 1999 CDT
> (1 row)
>
> template1=> select date_trunc('month', now()) = '9/1/1999';
> ?column?
> --------
> t
> (1 row)
>
> Enjoy,
> DEJ
>
> > -----Original Message-----
> > From: Paulo Roberto Kappke [SMTP:paulok@cyclades.com.br]
> > Sent: Wednesday, September 22, 1999 8:13 AM
> > To: pgsql-sql@postgreSQL.org
> > Subject: [SQL] Date type select
> >
> > Hi all,
> >
> > I'm having a problem to make a select statement with a date type field.
> >
> > I have a table with a field named date_in and this field is a date type.
> > Well, I need to do a select where the month is 09 and the year is 1999.
> > I tried:
> >
> > SELECT * FROM calls WHERE date_in LIKE '09%1999' ORDER BY date_in
> >
> > or
> >
> > SELECT * FROM calls WHERE date_in LIKE '09-__-1999' ORDER BY date_in
> >
> > or
> >
> > SELECT * FROM calls WHERE date_in LIKE '09%' AND date_in LIKE '%1999'
> > ORDER BY date_in
> >
> > using psql command and I received the following message:
> >
> > ERROR: There is more than one possible operator '~~' for types 'date'
> > and 'unknown'
> > You will have to retype this query using an explicit cast
> >
> >
> > Could anybody help me ?
> >
> >
> > Thanks in advance,
> > Paulo Kappke
> > Cyclades Brazil
> >
> > ************
