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Thread: Query for duplicates.

Query for duplicates.

From
Matthew Hagerty
Date:
Greetings,

I found myself in an unusual situation today.  I need a query to display
only customers with addresses that appear more than once.  Usually I am
having to get unique addresses, etc. at which I have become very good, but
this one is giving me a run for.

What I need is something like this:

create table customer (
custdate date,
name varchar(30),
address varchar(30),
city varchar(20),
state varchar(2),
zip varchar(10));


select address,city,state,zip from customer
where custdate<='05-30-1999'
group by address having count(address)>1;


I know this does not work, but if it did it would have the results I am
looking for.

Thanks,
Matthew

Re: [SQL] Query for duplicates.

From
"John M. Flinchbaugh"
Date:
On Thu, 5 Aug 1999, Matthew Hagerty wrote:
> I found myself in an unusual situation today.  I need a query to display
> only customers with addresses that appear more than once.  Usually I am
> having to get unique addresses, etc. at which I have become very good, but
> this one is giving me a run for.
> What I need is something like this:
> create table customer (
> custdate date,
> name varchar(30),
> address varchar(30),
> city varchar(20),
> state varchar(2),
> zip varchar(10));
> select address,city,state,zip from customer
> where custdate<='05-30-1999'
> group by address having count(address)>1;

select address,city,state,zip from customer
where custdate<='05-30-1999'
group by address,city,state,zip
having count(*)>1;

____________________}John Flinchbaugh{______________________
| -> glynis@hjsoft.com <-             john@cs.millersv.edu |
|    glynis@netrax.net      http://www.hjsoft.com/~glynis/ |
~~Powered by Linux: Reboots are for hardware upgrades only~~

Re: [SQL] Query for duplicates.

From
Matthew Hagerty
Date:
Thanks, that works great!

Matthew

At 04:19 PM 8/5/99 -0400, John M. Flinchbaugh wrote:
>On Thu, 5 Aug 1999, Matthew Hagerty wrote:
>> I found myself in an unusual situation today.  I need a query to display
>> only customers with addresses that appear more than once.  Usually I am
>> having to get unique addresses, etc. at which I have become very good, but
>> this one is giving me a run for.
>> What I need is something like this:
>> create table customer (
>> custdate date,
>> name varchar(30),
>> address varchar(30),
>> city varchar(20),
>> state varchar(2),
>> zip varchar(10));
>> select address,city,state,zip from customer
>> where custdate<='05-30-1999'
>> group by address having count(address)>1;
>
>select address,city,state,zip from customer
>where custdate<='05-30-1999'
>group by address,city,state,zip
>having count(*)>1;
>
>____________________}John Flinchbaugh{______________________
>| -> glynis@hjsoft.com <-             john@cs.millersv.edu |
>|    glynis@netrax.net      http://www.hjsoft.com/~glynis/ |
>~~Powered by Linux: Reboots are for hardware upgrades only~~
>
>