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Thread: UPDATE (SELECT ) is not working................

UPDATE (SELECT ) is not working................

From
Archana K N
Date:
Hello,

     I am trying to update a database with values from another . Am using Debain(Linux) OS.

        When I try to update no error is displayed. But column is not updated.
I am using the psql console for querying.

my code is as follows(along with result):-

""my_db=# update test set id=g.id2 from (select id2 from test2)as g ;
UPDATE 0
""
 
Thanks in advance............
--
-------------------
regards
archana
--------------------

Re: UPDATE (SELECT ) is not working................

From
Andrew McMillan
Date:
On Fri, 2014-01-17 at 13:58 +0530, Archana K N wrote:
> Hello,
>
>
>      I am trying to update a database with values from another . Am
> using Debain(Linux) OS.
>
>
>         When I try to update no error is displayed. But column is not
> updated.
> I am using the psql console for querying.
>
>
> my code is as follows(along with result):-
>
>
> ""my_db=# update test set id=g.id2 from (select id2 from test2)as g ;
> UPDATE 0

Your SQL does not do what you think it does.

You should probably test your SQL at the psql command line to figure out
the correct way to do what you want to do before you try and post to a
PHP mailing list about this kind of thing.

I'd offer advice, but I can't figure out from your statement what you're
trying to do your database either.

Cheers,
                    Andrew.


--
------------------------------------------------------------------------
andrew (AT) morphoss (DOT) com                         +64 (2) 7233 2426
                        IOT trap -- core dumped
------------------------------------------------------------------------

Re: UPDATE (SELECT ) is not working................

From
Archana K N
Date:
Hi,

     Sorry  it is not 'database' ,but 'table' . I followed the syntax given 

UPDATE table_name SET(columns) FROM (SELECT columns FROM table_2) AS som-val WHERE condition;

And I tried it in psql command line as

my_db=# update test set id=g.id2 from (select id2 from test2)as g ;
 UPDATE 0

where my_db is the database I created.

regards
archana


On Fri, Jan 17, 2014 at 2:34 PM, Andrew McMillan <andrew@morphoss.com> wrote:
On Fri, 2014-01-17 at 13:58 +0530, Archana K N wrote:
> Hello,
>
>
>      I am trying to update a database with values from another . Am
> using Debain(Linux) OS.
>
>
>         When I try to update no error is displayed. But column is not
> updated.
> I am using the psql console for querying.
>
>
> my code is as follows(along with result):-
>
>
> ""my_db=# update test set id=g.id2 from (select id2 from test2)as g ;
> UPDATE 0

Your SQL does not do what you think it does.

You should probably test your SQL at the psql command line to figure out
the correct way to do what you want to do before you try and post to a
PHP mailing list about this kind of thing.

I'd offer advice, but I can't figure out from your statement what you're
trying to do your database either.

Cheers,
                                        Andrew.


--
------------------------------------------------------------------------
andrew (AT) morphoss (DOT) com                         +64 (2) 7233 2426
                        IOT trap -- core dumped
------------------------------------------------------------------------




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--
-------------------
regards
archana
--------------------

Re: UPDATE (SELECT ) is not working................

From
Mark Kirkwood
Date:
On 17/01/14 21:28, Archana K N wrote:

>
> ""*/my_db=# update test set id=g.id2 from (select id2 from test2)as g ;/*
> */UPDATE 0/*
> ""
>

'UPDATE 0' means 0 rows where found to update. So everything is working
fine, but your query search criteria is finding no candidate rows to
change. This is purely a data issue.

Regards

Mark