Thread: HTML FORMS selected question

Mag Gam wrote:
> I am having trouble getting values populated in my form... Here is what
> I got so far:
>
> //The values that need to be selected
> $result_ip=pg_query($dbconn,$test_query);
>
> <SELECT    NAME="ip[]" SIZE=10 MULTIPLE>
> <?php
> //This will show ALL values.
> while($rows=pg_fetch_array($result)){
> foreach ($options as $index => $option) {
>     if ($rows[1]==$option)
>     {


What does $rows contain? What does $options contain?

You could also simplify this a little bit. I'd at least remove the
foreach $options loop and use "in_array" - see php.net/in_array

while ($rows = pg_fetch_array($result)) {
   $selected = '';
   if (in_array($rows[1], $options)) {
     $selected = ' SELECTED';
   }
   sprintf('<option value="%s"%s>%s</option>', $rows[1], $selected,
$rows[1]);
}

--
Postgresql & php tutorials
http://www.designmagick.com/

Please CC the list so they can suggest things and learn as well.

Mag Gam wrote:
> Hi Chris:
>
> $rows is an array of all the values
> $options is an array of all the values selected

I meant can you give an example of what they both contain?

I know what they *should* contain - what do they *actually* contain?

--
Postgresql & php tutorials
http://www.designmagick.com/

Maybe it's just a typo, but your pg_query is returning into the var
$result_ip, while your fetch is referencing var $result (without _ip).
Maybe that's just a typo for your question, but if not, that is at least one
error.

Also, it would be helpful to know what error you're getting....

Randy Moller

-----Original Message-----
From: pgsql-php-owner@postgresql.org [mailto:pgsql-php-owner@postgresql.org]
On Behalf Of Chris
Sent: Sunday, December 03, 2006 4:08 PM
To: Mag Gam
Cc: pgsql-php@postgresql.org
Subject: Re: [PHP] HTML FORMS selected question

Mag Gam wrote:
> I am having trouble getting values populated in my form... Here is what
> I got so far:
>
> //The values that need to be selected
> $result_ip=pg_query($dbconn,$test_query);
>
> <SELECT    NAME="ip[]" SIZE=10 MULTIPLE>
> <?php
> //This will show ALL values.
> while($rows=pg_fetch_array($result)){
> foreach ($options as $index => $option) {
>     if ($rows[1]==$option)
>     {


What does $rows contain? What does $options contain?

You could also simplify this a little bit. I'd at least remove the
foreach $options loop and use "in_array" - see php.net/in_array

while ($rows = pg_fetch_array($result)) {
   $selected = '';
   if (in_array($rows[1], $options)) {
     $selected = ' SELECTED';
   }
   sprintf('<option value="%s"%s>%s</option>', $rows[1], $selected,
$rows[1]);
}

--
Postgresql & php tutorials
http://www.designmagick.com/

---------------------------(end of broadcast)---------------------------
TIP 6: explain analyze is your friend

--
No virus found in this incoming message.
Checked by AVG Free Edition.
Version: 7.5.430 / Virus Database: 268.15.6/565 - Release Date: 12/2/2006
9:39 PM


--
No virus found in this outgoing message.
Checked by AVG Free Edition.
Version: 7.5.430 / Virus Database: 268.15.6/565 - Release Date: 12/2/2006
9:39 PM

Mag Gam wrote:
> Randy + Chris:
>
> Thx for the quick replies!
>
> Chris:
>
> $rows contain ip addresses (postgresql inet) type (example: 192.168.0.1
> <http://192.168.0.1>)
> $options contain ip addresses (postgresql inet0 type (example: 127.0.0.1
> <http://127.0.0.1>)
> (keep in mind) they are both arrays. $rows contact all ips, and $options
> contact the ip addresses that were selected
>
> Randy:
> I am not sure what you mean. The variables look right. I am getting no
> errors! Just the logic is messed up.

I think Randy's right.

At the top you have:

//The values that need to be selected
$result_ip=pg_query($dbconn,$test_query);
^^^^^^^^^
but you are doing this:

while ($row = pg_fetch_array($result)) {


$result_ip  at the top, $result in the second bit.


If you don't see errors, turn up error reporting & display errors:

error_reporting(E_ALL);
ini_set('display_errors', true);


Also that's not what I meant. I meant add a var_dump or print_r at each
stage to see what you are *really* getting from the code.


--
Postgresql & php tutorials
http://www.designmagick.com/

--
No virus found in this outgoing message.
Checked by AVG Free Edition.
Version: 7.5.430 / Virus Database: 268.15.6/565 - Release Date: 12/2/2006 9:39 PM

Mag Gam wrote:
> Chris + Randy:
>
> Sorry, I may of forgetten to give you this:
> $result = pg_query($dbconn, "select id,address from ip");
>
> This is right before the:
> $options=pg_fetch_array($result_ip);
>
> so, my $results is really all the ip addresses ($rows after I perform
> the pg_fetch_array).
>
> I will add the var_dump to see it (never done it before, I will do some
> googling :) )

After your query add it:

$result = pg_query(....)
var_dump($result);

if that's not a "resource" then you have a problem with your query. Use
pg_last_error to work it out.


Inside your loop, add it:

while ($row = pg_fetch_array($result)) {
   var_dump($row);
}

--
Postgresql & php tutorials
http://www.designmagick.com/