This is a little complex to explain - so its probably better with an example..
I don't know if theres some inbuilt function to tell you what datatype a value
is - so 'kludged' this together :
CREATE OR REPLACE FUNCTION rval_type(m date) RETURNS text AS $$ BEGIN RETURN 'it was a date'; END; $$
LANGUAGEplpgsql;
CREATE OR REPLACE FUNCTION rval_type(m text) RETURNS text AS $$ BEGIN RETURN 'it was a text'; END; $$
LANGUAGEplpgsql;
CREATE OR REPLACE FUNCTION rval_type(m int) RETURNS text AS $$ BEGIN RETURN 'it was a int'; END; $$
LANGUAGEplpgsql;
Now - if I have a cpc containing :
main() { exec sql begin declare section; date d; int i; char a[200]; char lv_out[200]; exec sql end declare
section;
exec sql database test1;
d=0; i=0; strcpy(a,"-"); memset(lv_out,0,sizeof(lv_out));
exec sql select rval_type(:d) into :lv_out; if (sqlca.sqlcode<0) sqlprint(); else printf("%s\n",lv_out);
exec sql select rval_type(:i) into :lv_out; if (sqlca.sqlcode<0) sqlprint(); else printf("%s\n",lv_out);
exec sql select rval_type(:a) into :lv_out; if (sqlca.sqlcode<0) sqlprint(); else printf("%s\n",lv_out);
}
You can see I'm passing in a date, then an integer, then a character string.
However - when you run the code you get :
it was a text
it was a text
it was a text
This to me looks 'wrong', especially when previous versions of ecpg (<8.0?)
gave the correct :
it was a date
it was a int
it was a text
Any thoughts ?
(This is manifesting itself as arithmetic errors when I'm using dates in my
application)
--
Mike Aubury
Aubit Computing Ltd is registered in England and Wales, Number: 3112827
Registered Address : Clayton House,59 Piccadilly,Manchester,M1 2AQ
