Thread: order by in cursor declaration does not allow update
If a cursor is declared using "Order by" then it gives following error <br /> during updation of the cursor: <br /> ERROR: cursor "c" is not a simply updatable scan of table "test" <br /> Ex: <br /> DROP TABLE IF EXISTS test;<br /> createtable test (num int,num2 int );<br /> insert into test values(1,100);<br /> insert into test values(2,200);<br /> insertinto test values(3,300);<br /> insert into test values(4,400);<br /> insert into test values(5,500);<br /> BEGIN; <br/> DECLARE c CURSOR FOR SELECT * FROM test ORDER BY num; <br /> FETCH 2 FROM c; <br /> UPDATE test SET num = 500 WHERECURRENT OF c; <br /> ERROR: cursor "c" is not a simply updatable scan of table "test" <br /> SELECT * FROM test; <br/> FETCH 2 FROM c; <br /> COMMIT; <br /> SELECT * FROM test; <br /> FETCH 2 FROM c; <br /> COMMIT;<br /><br /> Commentsfor this...??<br /><br /> Regards,<br /> Dharmendra<br /><a href="http://www.enterprisedb.com">www.enterprisedb.com</a><br/>
On Thu, 2007-10-25 at 12:28 +0530, Dharmendra Goyal wrote: > If a cursor is declared using "Order by" then it gives following > error > during updation of the cursor: > ERROR: cursor "c" is not a simply updatable scan of table "test" > Ex: > DROP TABLE IF EXISTS test; > create table test (num int,num2 int ); > insert into test values(1,100); > insert into test values(2,200); > insert into test values(3,300); > insert into test values(4,400); > insert into test values(5,500); > BEGIN; > DECLARE c CURSOR FOR SELECT * FROM test ORDER BY num; > FETCH 2 FROM c; > UPDATE test SET num = 500 WHERE CURRENT OF c; > ERROR: cursor "c" is not a simply updatable scan of table "test" > Comments for this...?? You haven't specified FOR UPDATE on the query in the DECLARE clause. -- Simon Riggs 2ndQuadrant http://www.2ndQuadrant.com
According to SQL specifications: If "READ ONLY" is not specified in cursor declaration then for update is
implicit.
Anyway, even if i specify "for update" in the declare clause, behaviour is same.
DROP TABLE IF EXISTS test;
create table test (num int,num2 int );
insert into test values(1,100);
insert into test values(2,200);
insert into test values(3,300);
insert into test values(4,400);
insert into test values(5,500);
BEGIN;
DECLARE c CURSOR FOR SELECT * FROM test ORDER BY num FOR UPDATE;
FETCH 2 FROM c;
UPDATE test SET num = 500 WHERE CURRENT OF c;
ERROR: cursor "c" is not a simply updatable scan of table "test"
SELECT * FROM test;
FETCH 2 FROM c;
COMMIT;
SELECT * FROM test;
FETCH 2 FROM c;
COMMIT;
Regards,
Dharmendra
www.enterprisedb.com
On 10/25/07, Simon Riggs <simon@2ndquadrant.com> wrote:
On Thu, 2007-10-25 at 12:28 +0530, Dharmendra Goyal wrote:
> If a cursor is declared using "Order by" then it gives following
> error
> during updation of the cursor:
> ERROR: cursor "c" is not a simply updatable scan of table "test"
> Ex:
> DROP TABLE IF EXISTS test;
> create table test (num int,num2 int );
> insert into test values(1,100);
> insert into test values(2,200);
> insert into test values(3,300);
> insert into test values(4,400);
> insert into test values(5,500);
> BEGIN;
> DECLARE c CURSOR FOR SELECT * FROM test ORDER BY num;
> FETCH 2 FROM c;
> UPDATE test SET num = 500 WHERE CURRENT OF c;
> ERROR: cursor "c" is not a simply updatable scan of table "test"
> Comments for this...??
You haven't specified FOR UPDATE on the query in the DECLARE clause.
--
Simon Riggs
2ndQuadrant http://www.2ndQuadrant.com
On Thu, 2007-10-25 at 16:53 +0530, Dharmendra Goyal wrote: > According to SQL specifications: If "READ ONLY" is not specified in cursor declaration then for update is > implicit. Though that isn't what the PostgreSQL docs say. -- Simon Riggs 2ndQuadrant http://www.2ndQuadrant.com
"Dharmendra Goyal" <dharmendra.goyal@gmail.com> writes: > If a cursor is declared using "Order by" then it gives following error > during updation of the cursor: > ERROR: cursor "c" is not a simply updatable scan of table "test" This is not a bug. (See also quote from SQL92 in the other thread.) regards, tom lane