>>
>> > Point taken. So, if the spaces are used, then a>-2 is not
>> the same as a>-
>> > 2. The latter should then generate an error, right?
>>
>> It wasn't real clear where you intended to insert whitespace in this
>> example... but in any case, it might or might not generate an error
>> depending on what operators have been defined. Both "a >- 2" (three
>> tokens) and "a > - 2" (four tokens) might be legal expressions.
>> If they are not, it's not the lexer's job to figure that out.
Yes, and -2 is two tokens, whether it's - 2 or -2. Taking the unary minus
and the number, and creating a single expression meaning two less than zero
is not the lexer's job. Or is it? Or am I missing the plot?
MikeA
