Thread: How to return an INT4 subtracting dates?
Hi,
I need to return an int4 subtracting two dates, but returns me an interval.
select
end_date - now() as interger_number
from hist_anuncios
How to return an integer out of this?
Best Regards,
I need to return an int4 subtracting two dates, but returns me an interval.
select
end_date - now() as interger_number
from hist_anuncios
How to return an integer out of this?
Best Regards,
Hello 2010/6/9 Andre Lopes <lopes80andre@gmail.com>: > Hi, > > I need to return an int4 subtracting two dates, but returns me an interval. > > select > end_date - now() as interger_number > from hist_anuncios > > How to return an integer out of this? > > > Best Regards, > > postgres=# select '2010-06-18'::date - CURRENT_DATE; ?column? ---------- 9 (1 row) Regards pavel Stehule
On 09/06/2010 11:57, Andre Lopes wrote: > Hi, > > I need to return an int4 subtracting two dates, but returns me an interval. > > select > end_date - now() as interger_number > from hist_anuncios > > How to return an integer out of this? Hmmm, according to the docs, subtracting dates returns an integer: http://www.postgresql.org/docs/8.4/static/functions-datetime.html Try "current_date", which gives you a date, instead of "now", which gives you a timestamp. Ray. -- Raymond O'Donnell :: Galway :: Ireland rod@iol.ie