Thread: where column in ARRAY

Without building up a dynamic query is it possible to:

create or replace function t1(a int[]) as
$$
...
select * from t1 where c in a; // eg in spite of in (1,2,3);

or just obtain a similar effect?

--
Ivan Sergio Borgonovo
http://www.webthatworks.it

Hi,

http://www.postgresql.org/docs/current/static/arrays.html

# SELECT 1 = ANY ('{1,2,3}'::integer[]);
 ?column?
----------
 t

Ludo

On Wed, Oct 22, 2008 at 2:46 PM, Ivan Sergio Borgonovo
<mail@webthatworks.it> wrote:
> Without building up a dynamic query is it possible to:
>
> create or replace function t1(a int[]) as
> $$
> ...
> select * from t1 where c in a; // eg in spite of in (1,2,3);
>
> or just obtain a similar effect?
>
> --
> Ivan Sergio Borgonovo
> http://www.webthatworks.it
>
>
> --
> Sent via pgsql-general mailing list (pgsql-general@postgresql.org)
> To make changes to your subscription:
> http://www.postgresql.org/mailpref/pgsql-general
>

On Wed, 22 Oct 2008 14:46:35 +0200
Ivan Sergio Borgonovo <mail@webthatworks.it> wrote:

> Without building up a dynamic query is it possible to:
>
> create or replace function t1(a int[]) as
> $$
> ...
> select * from t1 where c in a; // eg in spite of in (1,2,3);
>
> or just obtain a similar effect?

tired rally tired... I didn't understand the example in the manual
where on the left side there is a constant and the column is the
array.
ANY works the other way around as well.

select * from t1 where c=any(a);

too much assembly language in my youth.

Sorry for the noise.

--
Ivan Sergio Borgonovo
http://www.webthatworks.it