Fill an array with "Absent".
Do a select that will pull the correct entries.
Do a loop and overwrite the appropriate array elements with "Worked" based
on the select results.
Then display the array.
Hopefully this helps,
Jeff Post
-----Original Message-----
From: pgsql-general-owner@postgresql.org
[mailto:pgsql-general-owner@postgresql.org]On Behalf Of Ben-Nes Michael
Sent: Sunday, June 30, 2002 7:33 AM
To: pgsql-general@postgresql.org
Subject: [GENERAL] SQL Puzzle
Hi All
I have a table where all worker logon and out every day:
table columns: record_id, worker, log_time, status, description
If a worker was absent there will be no record for the current day.
Now, I want to query this table to get a list of all days in month and in an
aditional field i would like to put worked/abscent ( depends if he was or
was not )
Is it possible in SQL ?
I thought about fuction with 'for' from 1 to 30 then subselect to check if
worker worked on a current day but its a complicated solution.
Does any body have idea for easier method ?
I can do it easily in php but i want to do as maximum as I can on the db
itself.
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