I'm using PostgreSQL version 7.1, and I'm having trouble with the LIKE
statement. How would I find the value "a\bc"? I tried using the
backslash to escape it: LIKE 'a\\b%';
If I specify: LIKE 'a\\bc', then it works, but if I wanted it to look
for consecetive characters after the c, using the %, then it returns
other values besides what I'm looking for.
I also have the same problem with percent (%). I have a test string
with the value "ab%c", and I want to look for that using LIKE. I tried:
LIKE 'ab\\%c', LIKE 'ab%%', and LIKE 'ab%_', but these statements not
only returned what I was looking for, but also other values: "abc",
"ABC", and "Abc".
Phuong
