I really have no idea what you are truly asking for here, but here's a
crack at what I think you want.
select count(p.*) from prestito p, libro l
where p.id_libro = l.id_libro
group by p.id_utente, l.tipo
Try it...
-DEJ
> -----Original Message-----
> Hi again,
> I have this 3 tables:
> esame=> select * from prestito\g
> id_libro|id_utente|data_prestito|visto|notifica1|notifica2|notifica3
> --------+---------+-------------+-----+---------+---------+---------
> 11| 37| 12-04-1998|f | | |
> (1 row)
>
> esame=> select * from utente\g
> cognome |nome |id_utente|indirizzo |
> telefono|tipo_utente|info_utente |l
> ibri_presi| notifica1| notifica2| notifica3|password|email
> --------+--------+---------+----------------+------------+-----------+
> ------------------+-
> ----------+----------+----------+----------+--------+--------------
> Ballabio|Dario | 37|Via carducci 125| 02-2422700|
> 1|Ditta Enter S.r.L.|
> | | | |dario |dario@pinco.it
>
> esame=> select * from libro\g
> titolo |id_libro|id_utente|collocazione|casa_edit|
> data_publ|tipo|difetto|id_libro_ke
> y
> ------------+--------+---------+------------+---------+----------+----
> +-------+-----------
> -
> Il talismano|s1 | 0|d1 |aop2 |05-12-1985|
> 1|
> | 1
> 2
> It |d1 | 37|d1 |apo |05-12-1940|
> 1|
> | 1
> 1
>
> I need a query that for each id_utente return me the numeber of items
> in
> "prestito" and th
> is number is group by libro.tipo
>
>
>
> "Il divertimento e' giusto se la scimmia ci prende gusto"
> --
> Italian Linux Press: http://ziobudda.enter.it/ILP/
> --
> Morelli 'ZioBudda' Davide Michel - Member of Pluto Linux User Group
> michel@michel.enter.it - http://ziobudda.enter.it/
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