Stephan, Joseph,
> Because d.id was guaranteed to be unique, you might be able to
> count(distinct d.id) and get the result you want. [I think the
> subquery is a nicer way of representing it]
Plus a several SQL implementations don't implement the DISTINCT until
after the COUNT, reuslting in a still-inflated (and sometimes varying!)
COUNT. It won't work properly in T-SQL or MS Office SQL, for example.
-Josh Berkus
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